Answer to the problem you are asking is d
.Vertex: <span><span>(<span>3,1</span>)</span><span>3,1</span></span>Focus: <span>(<span>3,<span>9/8</span></span>)</span>Axis of Symmetry: <span>x=3</span>Directrix: <span>y=<span>7/8
</span></span>
Select a few x values, and plug them into the equation to find the corresponding y values. The x
values should be selected around the vertex.
Graph<span> the </span>parabola<span> using its properties and the selected </span>points<span>.
</span>
Vertex<span>: </span><span>(<span>3,1</span><span>)
</span></span>
Focus<span>: </span><span>(<span>3,<span>9/8</span></span><span>)
</span></span>
Axis of Symmetry: <span><span>x</span><span>=3</span></span>Directrix: <span>y=<span><span>7/8
x= 1,2,3,4,5
y= 9,3,1,3,9 </span></span></span>
Answer:
4 DLLS
Step-by-step explanation:
Answer with explanation:
The equation of two planes are
1.→y +2 z=10
2.→x+y=11
To find the point of Intersection of two planes
let,→ y=t
→2 z=10 - t
10 -2 z=t
→x=11 -t
11 -x=t
So,Writing equation of line which is intersection of two planes
→ 11 -x = y= 10-2 z=t
---------------------------------(1)
⇒Putting , x=0, y=0 and z=0 in the above equation ,to find the point Closest to Origin which will be
=(11, 0, 10)
Answer:
The answer is D and B trust me 100%
Step-by-step explanation:
