Answer:
-0.9231
Step-by-step explanation:
Given cos theta = 0.3846 within the range 3π/2<theta<2π
Costheta = 0.3846
Theta = arccos(0.3846)
Theta = 67.38°
Since 67.38° didn't fall within the range of theta, we will locate our theta using the quadrant.
Since cos is positive in the 4th quadrant,
Theta = 360-67.38°
Theta = 292.62°
Sin(theta) = sin(292.62°)
= -0.9231
I order to do this question, you need to put the 13 on the right side. So now you have x^2+12x+0=13. Now, take half of 12, and square it. Add this to both sides to get x^2+12x+36=49. Now factor the left side by putting the half of 12 into this blank to get, (x+_)^2=49. Final Answer is,
(x+6)^2=49.
Answer:
Step-by-step explanation:
450
We are to solve the total area of the pyramid and this can be done through area addition. We first determine the area of the base using the Heron's formula.
A = √(s)(s - a)(s - b)(s - c)
where s is the semi-perimeter
s = (a + b + c) / 2
Substituting for the base,
s = (12 + 12 + 12)/ 2 = 18
A = (√(18)(18 - 12)(18 - 12)(18 - 12) = 62.35
Then, we note that the faces are just the same, so one of these will have an area of,
s = (10 + 10 + 12) / 2 = 16
A = √(16)(16 - 12)(16 - 10)(16 - 10) = 48
Multiplying this by 3 (because there are 3 faces with these dimensions, we get 144. Finally, adding the area of the base,
total area = 144 + 62.35 = 206.35
