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2 years ago

Help!what is the answer to this problem?

Mathematics

1 answer:

Rudiy272 years ago

4 0

Answer:

Step-by-step explanation:

Because 12 is greater than -5 and when you divide a postive and a negative you get a negative number. And negative numbers are less than 0 .

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I need this answered, hurry

adoni [48]

If I'm correct the answer would be C.) hope this help

8 0

2 years ago

Take a square sheet of paper 20 cm by 20 cm, cut identical squares from each corner, and fold up the flaps to make a box (withou

iris [78.8K]

The maximum possible volume of this type of box that can be made from a 20 cm by 20 cm square of paper is 512cm³.

<h3>How to calculate the volume?</h3>

From the information, when the side of 1cm are cut, this will become an open box. The volume will be:

= 18 × 18 × 1

= 324cm³

Also, when 2cm is cut, the volume will be:

= 16 × 16 × 2

= 512cm³

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brainly.com/question/1972490

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3 0

1 year ago

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2

Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is $\frac{1}{20000}$

Probability of getting second prize is $\frac{2}{20000}$

Probability of getting third prize is $\frac{20}{20000}$

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

$\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10$

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is $\frac{19977}{20000}$

The expected value is

$E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25$

$E=\frac{1000+600+200-4994.25}{20000}$

$E=\frac{-3194.25}{20000}$

$E=-0.159$

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

3 0

2 years ago

Which ordered pair is a solution to - 8x + 6y <3x - 30?

Ivenika [448]

Answer:

B ( 6,-6) ..

I think I'm correct

4 0

2 years ago

Read 2 more answers

HELP HOW DO YOU WORK THIS OUT!!

Harrizon [31]

Answer:

I believe it would be 4/6

Step-by-step explanation:

You have four different ways to get a sum of 7: 1 and 6; 2 and 5; 3 and 4; or 4 and 3.

4 0

3 years ago

Help!what is the answer to this problem?​

Help!what is the answer to this problem?