Answer: width = 300
<u>Step-by-step explanation:</u>
Area (A) = Length (L) x width (w)
Given: A = 268,500
L = 3w - 5
w = w
268,500 = (3w - 5) x (w)
268,500 = 3w² - 5w
0 = 3w² - 5w - 268,500
0 = (3w + 895) (w - 300)
0 = 3w + 895 0 = w - 300
-985/3 = w 300 = w
Since width cannot be negative, disregard w = -985/3
So the only valid answer is: w = 300
Answer:
A) 1/9, 3, 27
Step-by-step explanation:
i think you mean 3^x (and not 3x).
because otherwise none of the answer options withdraw makes any sense.
3^-2 = 1/(3²) = 1/9
3¹ = 3
3³ = 27
Answer:
D.) -3
Step-by-step explanation:
N is greater than -4 and less than -2.
Therefore, -3 is N since it is between -4 and -2.
We want to know the time, <em>t</em>, it takes the ball to reach a height (<em>y</em>) of 0.

We can factor out the GCF first. The largest number that will divide evenly into 16 and 24 is 8. Also, both terms have a <em>t</em>, so we can factor that out as well:

(-16/8 = -2 and 24/8 = 3)
Using the zero product property, we know that either 8t=0 or -2t+3=0. Solving the first equation, we would divide both sides by 8:
8t/8=0/8
t=0
This is at 0 seconds, before the ball is in the air at all.
Solving the second equation, we start by subtracting 3 from both sides:
-2t+3-3=0-3
-2t=-3
Now we divide both sides by -2
-2t/-2=-3/-2
t=1.5
After 1.5 seconds, the ball will hit the ground again.