Pls help i don’t understand this lolllll

andre [41]

The y-intercept (where x = 0) of the equation is at -20.

For every 60 the x runs, the y falls by -10. Use rise over run to determine the slope of the equation.

$\frac{-10}{60} = - \frac{1}{6}$

Slope-intercept form is determined by the following equation:

$y = mx + b$

m is your slope, and b is your y-intercept.

Plug the slope and y-intercept into the equation.

$y = -\frac{1}{6}x - 20$

4 0

3 years ago

Read 2 more answers

Help me with this please

kolbaska11 [484]

Answer:

5

Step-by-step explanation:

3 0

3 years ago

Please answer all i need help Factor the expression using the GCF. 50x-60 Next one Factor the expression using the GCF. 16m+40 n

Anton [14]

Answer:

10(5x - 6).

8(2m + 5).

9(3 - 5c)

Step-by-step explanation:

Given that

50x-60

16m+40

27-45c

The greatest common factor is a measure of the highest number present inside, or common to all the numbers that were listed. To take this one at a time, we have....

50x - 60. The highest number common to both of them is 10, and thus, we have

50x - 60 = 10(5x - 6), and this is the solved part.

16m + 40. The greatest number that's present inside both numbers is 8, and thus we have

16m + 40 = 8(2m + 5) and this is the solved part.

27 - 45c. The greatest common number is 9, and as a result, we have

27 - 45c = 9(3 - 5c), and this is the solution we were searching for

7 0

3 years ago

Use the given transformation to evaluate the given integral, where r is the triangular region with vertices (0, 0), (8, 1), and

Jlenok [28]

We first obtain the equation of the lines bounding R.

For the line with points (0, 0) and (8, 1), the equation is given by:

$\frac{y}{x} = \frac{1}{8} \\ \\ \Rightarrow x=8y \\ \\ \Rightarrow8u+v=8(u+8v)=8u+64v \\ \\ \Rightarrow v=0$

For the line with points (0, 0) and (1, 8), the equation is given by:

$\frac{y}{x} = \frac{8}{1} \\ \\ \Rightarrow y=8x \\ \\ \Rightarrow u+8v=8(8u+v)=64u+8v \\ \\ \Rightarrow u=0$

For the line with points (8, 1) and (1, 8), the equation is given by:

$\frac{y-1}{x-8} = \frac{8-1}{1-8} = \frac{7}{-7} =-1 \\ \\ \Rightarrow y-1=-x+8 \\ \\ \Rightarrow y=-x+9 \\ \\ \Rightarrow u+8v=-8u-v+9 \\ \\ \Rightarrow u=1-v$

The Jacobian determinant is given by

$\left|\begin{array}{cc} \frac{\partial x}{\partial u} &\frac{\partial x}{\partial v}\\\frac{\partial y}{\partial u}&\frac{\partial y}{\partial v}\end{array}\right| = \left|\begin{array}{cc} 8 &1\\1&8\end{array}\right| \\ \\ =64-1=63$

The integrand x - 3y is transformed as 8u + v - 3(u + 8v) = 8u + v - 3u - 24v = 5u - 23v

Therefore, the integration is given by:

$63 \int\limits^1_0 \int\limits^{1}_0 {(5u-23v)} \, dudv =63 \int\limits^1_0\left[\frac{5}{2}u^2-23uv\right]^{1}_0 \\ \\ =63\int\limits^1_0(\frac{5}{2}-23v)dv=63\left[\frac{5}{2}v-\frac{23}{2}v^2\right]^1_0=63\left(\frac{5}{2}-\frac{23}{2}\right) \\ \\ =63(-9)=|-576|=576$

6 0

3 years ago

Which is a solution -2x-y=1 and -4x-2y=-1

grin007 [14]

Answer:

No solutions.

Step-by-step explanation:

-2x - y = 1

-4x - 2y = -1 Multiply the first equation By -2:

4x + 2y = -2 Adding:

0 = -3

which is absurd so there are no solutions.

7 0

3 years ago