Step-by-step explanation:
The vertical height traveled is given by
h = ut +- (1/2)g*t^2
where
u = 57 ft/s, initial speed
t = tme, s
g = 32 ft/s^2
After 3 seconds,
h = (57 ft/s)*(3 s) - (1/2)*(32 ft/s^2)*(3 s)^2
= 171 - 144
= 27 ft
Answer: 27 ft
You mesure it with a contracter
It is 4 i am not gonna lie
Answer:
y = 3
Step-by-step explanation:
Solve for y:
y + 3 = 9 - y
Add y to both sides:
y + y + 3 = (y - y) + 9
y - y = 0:
y + y + 3 = 9
y + y = 2 y:
2 y + 3 = 9
Subtract 3 from both sides:
2 y + (3 - 3) = 9 - 3
3 - 3 = 0:
2 y = 9 - 3
9 - 3 = 6:
2 y = 6
Divide both sides of 2 y = 6 by 2:
(2 y)/2 = 6/2
2/2 = 1:
y = 6/2
The gcd of 6 and 2 is 2, so 6/2 = (2×3)/(2×1) = 2/2×3 = 3:
Answer: y = 3
