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Lina20 [59]
3 years ago
15

What is the area of a sector with a central angle of 2π/9 radians and a diameter of 20.6 mm? use 3.14 for π and round your answe

r to the nearest hundredth. enter your answer as a decimal in the box.
this is just to help people:)

Mathematics
1 answer:
mr Goodwill [35]3 years ago
4 0

Answer:

37.03 sq. mm.

Step-by-step explanation:

A sector is "part" of a circle. The formula for area of a sector (in radians) is:

Area of sector = \frac{1}{2}r^2 \theta

Where

r is the radius (half of diameter)

\theta  is the central angle of the sector

In this problem, the diameter is given as 20.6, so radius would be:

Radius (r) = 20.6/2 = 10.3

The central angle is given as  \frac{2\pi}{9} radians

Now, we substitute and find the value for the area:

A=\frac{1}{2}r^2 \theta\\A=\frac{1}{2}(10.3)^2 (\frac{2\pi}{9})\\A=\frac{1}{2}(106.09)(\frac{2(3.14)}{9})\\A=53.045*0.698\\A=37.03

Thus,

Area of sector = 37.03 sq. mm.

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