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3 years ago

at a particular school 50% of students travel by bus. if this represents 600 children how many children attend the school

Mathematics

2 answers:

jenyasd209 [6]3 years ago

6 0

Answer:

1200

Step-by-step explanation:

hichkok12 [17]3 years ago

4 0

Answer:

1200 students at the school

Step-by-step explanation:

Let x be the total number of students at the school

50% ride the bus

600 students ride the bus

x*50% = 600

Changing to decimal form

.50x = 600

Divide each side by .5

.50x/.5 = 600/.5

x =1200

1200 students at the school

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Hat is the solution for the equation?

aleksandrvk [35]

Answer:

a = -2

Step-by-step explanation:

I'm assuming that the equation is a + 8/3 = 2/3, and you are supposed to solve for a.

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3 years ago

A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

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2 years ago

Rachel multiplied each side of x ≥ 2 by 3. She wrote the result as 3x ≤ 6. Explain the error Rachel made.

andrey2020 [161]

Answer:

Her mistake was to change the inequality sign from ≥ to ≤.

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2 years ago

LCD of (2/x^2) - (7/4x^2+12x)?

svlad2 [7]

Answer:

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2 years ago

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Margarita [4]

Answer:

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Step-by-step explanation:

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6 0

2 years ago

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