Answer:
I would need to see the variables to answer this questions.
-8(1 + 8n) - 8(6 - 4n) = -24
-8 - 64n - 48 + 32n = -24
-32n - 56 = -24
-32n = 32
n = -1
Split up each force into horizontal and vertical components.
• 300 N at N30°E :
(300 N) (cos(30°) i + sin(30°) j)
• 400 N at N60°E :
(400 N) (cos(60°) i + sin(60°) j)
• 500 N at N80°E :
(500 N) (cos(80°) i + sin(80°) j)
The resultant force is the sum of these forces,
∑ F = (300 cos(30°) + 400 cos(60°) + 500 cos(80°)) i
… … … + (300 sin(30°) + 400 sin(60°) + 500 sin(80°)) j N
∑ F ≈ (546.632 i + 988.814 j) N
so ∑ F has a magnitude of approximately 1129.85 N and points in the direction of approximately N61.0655°E.
I they each cost 6.21$ caz if u do 6.21 you get 74.53 but if you do 6.20 you get74.40 what ever u prefer
