The first one is 2x-3y/2
The second one is 1/x+2
The third one is (2x-5y)/(2x+5y)
The fourth one is x^2/z^2
Answer:
a = -5
b = -1
m = -1
Step-by-step explanation:
Piecewise function:
f(x)= -5, x=0
f(x)= −x^2+3x+a, 0<x<2
f(x)= mx + b 2≤x≤3
The mean value theorem is applicable if f(x) is continuous on the entire closed interval [0;3] and differentiable on the entire closed interval [0;3].
To satisfied that at x = 0
:
−x^2+3x+a = -5
Then, a = -5
Derivative of −x^2+3x-5 is -2x + 3 and derivative of mx + b is m, at x = 2:
-2(2) + 3 = m
-1 = m
Replacing the functions at x = 2
:
−x^2+3x-5 = -x + b
−(2)^2+3*2-5 = -2 + b
-3 + 2 = b
-1 = b
Answer:When a vertical line is placed across the plot of this relation, it intersects the graph more than once for some values of x. If a graph shows two or more intersections with a vertical line, then an input (x-coordinate) can have more than one output (y-coordinate), and y is not a function of x.
Step-by-step explanation:
Answer:
75%
Step-by-Step Explanation:
There are two ways to go about this.
1) We can simply put it as a fraction = 60/80.
Then since a fraction sign also means division, we divide 60 by 80 = 0.75
Then to change a decimal into a percentage, we multiply by 100% = 75%
So our answer is 75%
2) We can simply it after it is put into a fraction = 60/80 = 3/4
It should be common knowledge that 3/4 is 75% depending on what grade you are in.
But there you have it, whichever way you prefer, the answer is always 75%.
The probability that the students take both Advanced Weight Training and Advanced Spanish is the product of their individual probabilities.
P(A and B) = 0.099 = P(A) x P(B)
where A and B are the events in which a student takes Advance Weight Training and Advanced Spanish.
P(B) = P(A and B) / P(A)
Substituting the known values,
P(B) = 0.099 / 0.71 = 0.14
Thus, the answer is 0.14.
