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svetoff [14.1K]
3 years ago
6

1. Is the product of √16 and 4/7 rational or irrational? Explain your reasoning.

Mathematics
2 answers:
Neporo4naja [7]3 years ago
6 0

Answer:

1. Irrational

2. C irrational because one factor is irrational

Step-by-step explanation:

1. Product of √16 and 4/7

= \sqrt{16}\times\frac{4}{7}

⇒ 4\times\frac{4}{7}=\frac{16}{7} =2.28571428571

which is an irrational number because numbers after the decimal is repeating and non-terminating.

2. Product of √576 and √684

= √576 × √684

= 24 × 6√19 = 144√19 which is an irrational number.

Thus, option C is correct.

3. Given, a = √20 b = 2.5 c = √225

Then, a + b = √20 + 2.5 = 2√5 + 5.5

which is an irrational number because √5 is an irrational number.

Also, b + c = 2.5 + √225 = 2.5 + 15 = 17.5

which is rational number because decimal is terminating and non-repeating.

4. \frac{1}{3} +\frac{6\sqrt{5} }{7} = \frac{7+18\sqrt{5} }{21}

which is an irrational number because fraction include √5 also.

Thus, Jacob is not correct.

Mandarinka [93]3 years ago
3 0

1) Rational because the square root of 16 is 4 and 4 times 4/7 is a rational number (16/7)

2) Irrational because square root of 684 is irrational C

3) The square root of a is irrational so the answer is irrational. The square root of c is rational so the answer is rational.

4) Jacob is wrong because the square root of 5/7 is irrational so the answer to the problem is irrational.


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Mr. Roseanne will buy 12 1/2 pounds beef for for a cookout. The price for the first 3 pounds of beef is $4.99 per pound. After t
Yuri [45]

Answer:

As per the statement:

Mr. Roseanne will buy 12\frac{1}{2} pounds beef for for a cookout.

⇒ Weight of the beef he buy = \frac{25}{2} pounds.

It is given that:

The price for the first 3 pounds of beef is $4.99 per pound.

then;

the price for 3 pounds he will pay= 3 \times 4.99 =\$ 14.97

After that, the price is $4.49 per pound.

Remaining weight of beef left  = \frac{25}{2} -3 = \frac{19}{2} pounds.

then;

the price of \frac{19}{2} pounds he will pay = \frac{19}{2} \times 4.49= \$42.655

now, total money he will pay for the 12\frac{1}{2} pounds beef = 14.97+42.655 = \$57.625

Therefore, $57.625 will Mr. Roseanne pay for the beef


4 0
3 years ago
How many ounces of gold are in a 16​-karat gold chain that weighs 2.6 ​ounces?
oksano4ka [1.4K]

A 16 karat gold means that there are 16 parts of gold in 24 parts of the gold chain. Therefore the weight of the pure gold is:

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7 0
3 years ago
3q+4+9=-14 <br> what is Q
BlackZzzverrR [31]

Hi! Your answer is q = -9

Please see an explanation for a better and clear understanding to your problem.

Any questions about my answer and explanation can be asked through comments! :)

Step-by-step explanation:

Since we want to solve for q-term. That means we are going to isolate q-term.

\huge{3q+4+9=-14}

We can add 4 and 9 together.

\huge{3q+13=-14}

Because we want to know the value of q. That means we have to isolate q-term by subtracting both sides by 13.

\huge{3q+13-13=-14-13}\\\huge{3q=-27}

We are reaching to the final step where we divide the whole equation by 3.

\huge{\frac{3q}{3}=-\frac{27}{3}}\\\huge{q=-9}

Finally, the solution for this equation is q = -9. But what if you are not certain or sure about the answer? Let's check it out!

To check the answer, simply substitute q = -9 in the equation.

\huge{3q+4+9=-14}\\\huge{3(-9)+13=-14}\\\huge{-27+13=-14}\\\huge{-14=-14}

Notice that the equation is true for q = -9. Hence, we can conclude that the solution for this equation is q = -9.

Hope this helps!

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3 years ago
Which choices name a chord of circle F? Choose all answers that are correct. A. AD B. BE C. CF D. DF?
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I have encountered this problem before. The figure gave out 3 chords, 2 of which are diameters, and 1 radius.

A chord is a line segment that joins any two points on a circle. 

A diameter is the longest chord on a circle. It originates at one side of the circle, passes through the middle point of the circle, and end on another side of the circle.

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Among the choices: A.) AD and B.) BE are the chords.

CF and DF are radii. They only end up in the middle point of the circle.
8 0
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