Find the product.<br><br> 6.1 x 0.12<br><br><br> Pls I need some help I am timed hurry

Give four reasons why you think mathematics should be taught in primary schools

eimsori [14]

Answer:

Mathematics offers children a powerful way of communicating. They learn to explore and explain their ideas using symbols, diagrams and spoken and written language. Studying mathematics stimulates curiosity, fosters creativity and equips children with the skills they need in life beyond school.

Step-by-step explanation:

(It's not 4 though, I'm sorry)

8 0

3 years ago

13. 5/6+9/11

Juli2301 [7.4K]

Explanation:

Addition of fractions can be accomplished using the formula ...

a/b + c/d = (ad +bc)/(bd)

Usually, you are asked to find the common denominator and rewrite the fractions using that denominator. It is not necessary, but it can save a step in the reduction of the final result. Here, we'll use the formula, then reduce the result to lowest terms.

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13. 5/6 +9/11 = (5·11 +6·9)/(6·11) = 109/66 = 1 43/66

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14. 7/20 -5/8 = (7·8 -20·5)/(20·8) = -44/160 = -11/40

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15. 1/5 -1/12 = (1·12 -5·1)/(5·12) = 7/60

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Dividing fractions can be accomplished different ways. I was taught to multiply by the inverse of the divisor. ("Invert and multiply.") Here, that means the problem (2/7) / (1/13) can be rewritten as ...

(2/7) × (13/1) . . . . . where 13/1 is the inverse of 1/13.

You can also express the fractions over a common denominator. In that case, the quotient is the ratio of the numerators. Perhaps a little less obvious is that you can express the fractions using a common numerator. Then the quotient is the inverse of the ratio of the denominators: (2/7) / (2/26) = 26/7. (You can see how this works if you "invert and multiply" the fractions with common numerators. Those numerators cancel.)

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16. (2/7)/(1/13) = 2/7·13/1 = 26/7 = 3 5/7

8 0

4 years ago

Andy wrote the equation of a line that has a slope of Step 2: y plus 2 equals StartFraction 3 Over 4 EndFraction x minus StartFr

Archy [21]

Andy's equation is incorrect and the correct equation of the line is y + 2= 3/4(x - 3)

<h3>How to determine the equation of the line?</h3>

The given parameters are:

Slope, m = 3/4

Point, (x,y) = (3,-2)

The equation of the line is calculated using:

y - y1 = m(x - x1)

Substitute the known parameters

y + 2= 3/4(x - 3)

From the question;

Andy's equation is y + 2 = 3/4(x - 9/4)

The above equation is different from the actual equation y + 2= 3/4(x - 3)

Hence, Andy's equation is incorrect and the correct equation of the line is y + 2= 3/4(x - 3)

Read more about linear equations at:

brainly.com/question/1884491

#SPJ1

4 0

2 years ago

Solve y - 2x=3 for y.

NISA [10]

Answer:

y=2x+3

Step-by-step explanation:

y-2x=3

y=2x+3

4 0

3 years ago

Read 2 more answers

A company manufactures a brand of lightbulb with a lifetime in months that is normally distributed with mean 3 and variance 1. A

Ratling [72]

Answer:

The smallest number of bulbs to be purchased so that the succession of bulbs produces light for at least 40 months with probability at least 0.9772 is 16.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}$

$\Delta = b^{2} - 4ac$

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

n values from a normal distribution:

The mean is $\mu n$ and the standard deviation is $s = \sigma\sqrt{n}$

A company manufactures a brand of lightbulb with a lifetime in months that is normally distributed with mean 3 and variance 1.

This means that $\mu = 3, \sigma = \sqrt{1} = 1$

For n bulbs:

The distribution for the sum of n bulds has $\mu = 3n, \sigma = \sqrt{n}$

What is the smallest number of bulbs to be purchased so that the succession of bulbs produces light for at least 40 months with probability at least 0.9772?

We want that: $S_{n} \geq 40 = 0.9772$ .

This means that when X = 40, Z has a pvalue of 1 - 0.9772 = 0.0228, that is, when $X = 40, Z = -2$ . So

$Z = \frac{X - \mu}{\sigma}$

$-2 = \frac{40 - 3n}{\sqrt{n}}$

$-2\sqrt{n} = 40 - 3n$

$3n - 2\sqrt{n} - 40 = 0$

Using $y = \sqrt{n}$

$3y^2 - 2y - 40 = 0$

Which is a quadratic equation with $a = 3, b = -2, y = -40$

$\Delta = b^{2} - 4ac = (-2)^2 - 4(3)(-40) = 484$

$y_{1} = \frac{-(-2) + \sqrt{484}}{2*3} = 4$

$y_{2} = \frac{-(-2) - \sqrt{484}}{2*3} = -...$

Since y and n have both to be positive:

$y = \sqrt{n}$

$\sqrt{n} = 4$

$(\sqrt{n})^2 = 4^2$

$n = 16$

The smallest number of bulbs to be purchased so that the succession of bulbs produces light for at least 40 months with probability at least 0.9772 is 16.

4 0

3 years ago

Find the product. 6.1 x 0.12 Pls I need some help I am timed hurry