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3 years ago

11

PLEASE help me solve this problem. I really need help.

1 answer:

mote1985 [20]3 years ago

3 0

When:
a = b = 0 we have point (0,0).
a = 0 and b ≠ 0 vertical line segment from (0, -b) to (0, b)
a ≠ 0 and b = 0 horizontal line segment from (-a, 0) to (a, 0)
a ≠ 0 and b ≠ 0 a ≠ b ellipse
a ≠ 0 and b ≠ 0 a = b circle

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3 years ago

Suppose that lithium calculator battery with a charge of 3 volts, actually has a voltage with uniform distribution between 2.93

Dmitrij [34]

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Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

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$P(X \leq x) = \frac{x - a}{b-a}$

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3 years ago

Convert the Cartesian equation (x 2 + y 2)2 = 4(x 2 - y 2) to a polar equation.

SashulF [63]

<u>ANSWER</u>

${r}^{2} = 4 \cos2\theta$

<u>EXPLANATION</u>

The Cartesian equation is

${( {x}^{2} + {y}^{2} )}^{2} = 4( {x}^{2} - {y}^{2} )$

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This implies that

${( {r}^{2} )}^{2} = 4(( { r \cos\theta) }^{2} - {(r \sin\theta) }^{2} )$

Let us evaluate the exponents to get:

${r}^{4} = 4({ {r}^{2} \cos^{2}\theta } - {r}^{2} \sin^{2}\theta)$

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Divide through by r²

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Apply the double angle identity

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The polar equation then becomes:

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7 0

3 years ago