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3 years ago

Solve the equation please!

Mathematics

2 answers:

yKpoI14uk [10]3 years ago

6 0

Answer:

z=-60

Step-by-step explanation:

1/6z=-10

z=-10×6

z=-60

AlladinOne [14]3 years ago

3 0

test each number out

1/6*-60= -10

1/6*-4= -2/3

1/6*-5/3= -1.5

1/6*-16= -2 2/3

So the first one is the answer

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Step-by-step explanation:

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2(3.14)(2.5)=15.7 ft

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2 years ago

Prove the following statement.

gayaneshka [121]

Answer:

You can prove this statement as follows:

Step-by-step explanation:

An odd integer is a number of the form $2k+1$ where $k\in \mathbb{Z}$ . Consider the following cases.

Case 1. If $k$ is even we have: $(2k+1)^{2}=(2(2s)+1)^{2}=(4s+1)^{2}=16s^2+8s+1=8(2s^2+s)+1$ .

If we denote by $m=2s^2+2$ we have that $(2k+1)^{2}=8m+1$ .

Case 2. if $k$ is odd we have: $(2k+1)^{2}=(2(2s+1)+1)^{2}=(4s+3)^{2}=16s^2+24s+9=16s^{2}+24s+8+1=8(2s^{2}+3s+1)+1$ .

If we denote by $m=2s^{2}+24s+1$ we have that $(2k+1)^{2}=8m+1$

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6 0

3 years ago

Jenny is displaying her photographs

Inga [223]

Answer:

A) 9 photos in each row

B) 14 rows in total

Step-by-step explanation:

Photos of People = 45

Photos of Landscapes = 18

Photos of Pets = 63

Jenny wants to arrange these photos in rows with only one kind of photos in each row and same number of photos in each row. We have to find the greatest possible number of photos in each row. For this we need to find the greatest common factor of 45,18 and 63. This would give us the greatest possible number of photos that can be placed in each row.

By observing the 3 numbers, we can tell that the greatest common factor of these 3 numbers is 9. So, Jenny can place 9 photos in each row.

So,

There will be:

45/9 = 5 rows with photos of people

18/9 = 2 rows of photos of landscapes

63/9 = 7 rows of photos of pets

So, total number of rows would be = 5 + 2 + 7 = 14 rows

3 0

3 years ago