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adelina 88 [10]
3 years ago
7

PLEASE ANSWER ASAP!! WILL GIVE 50 POINTS! AND BRAINLIST!

Mathematics
1 answer:
levacccp [35]3 years ago
4 0

\frac{3}{5}  -  \frac{1}{4}  =  \frac{7}{20}
then
\frac{7}{20}  \div  \frac{7}{10}  =  \frac{1}{2}
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\bf \begin{array}{ccllll}
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\end{array}\implies \cfrac{\frac{2}{3}}{x}=\cfrac{\frac{1}{3}}{1}\implies \cfrac{\frac{2}{3}}{\frac{x}{1}}=\cfrac{\frac{1}{3}}{\frac{1}{1}}\\\\
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\bf \textit{now recall that }\qquad \cfrac{\frac{a}{b}}{\frac{c}{{{ d}}}}\implies \cfrac{a}{b}\cdot \cfrac{{{ d}}}{c}\\\\
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\cfrac{2}{3}\cdot \cfrac{1}{x}=\cfrac{1}{3}\cdot \cfrac{1}{1}\implies \cfrac{2}{3x}=\cfrac{1}{3}\implies 2\cdot 3=1\cdot 3x\implies 6=3x
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you have a quadratic equation that can be factored, like x2+5x+6=0.This can be factored into(x+2)(x+3)=0.

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2. 

<span><span>1. Try first to solve the equation by factoring.  Be sure that your equation is in standard form (ax2+bx+c=0) before you start your factoring attempt.  Don't waste a lot of time trying to factor your equation; if you can't get it factored in less than 60 seconds, move on to another method.
</span><span>2. Next, look at the side of the equation containing the variable.  Is that side a perfect square?  If it is, then you can solve the equation by taking the square root of both sides of the equation.  Don't forget to include a ± sign in your equation once you have taken the square root.
3.</span>Next, if the coefficient of the squared term is 1 and the coefficient of the linear (middle) term is even, completing the square is a good method to use.
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5 0
3 years ago
Read 2 more answers
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