<u>We are given the equation:</u>
(a + b)! = a! + b!
<u>Testing the given equation</u>
In order to test it, we will let: a = 2 and b = 3
So, we can rewrite the equation as:
(2+3)! = 2! + 3!
5! = 2! + 3!
<em>We know that (5! = 120) , (2! = 2) and (3! = 6):</em>
120 = 2 + 6
We can see that LHS ≠ RHS,
So, we can say that the given equation is incorrect
Answer:
70 units
Step-by-step explanation:
Answer:
It's option d.
Step-by-step explanation:
The line y = x + 2 has domain x < 2 (because of the clear circle.)
The lines y = x + 1 has domain x ≥ 2. ( because of the filled circle).
Number 2 is the answer to you question
X^3 + h^3 - 3x-3h - x^3 +3x h^3 - 3h h^2 - 2h
------------------------------------- = ------------------ =
h h
