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Marysya12 [62]
3 years ago
8

50 – 5(4.3 – 1.3) ÷ 0.5

Mathematics
2 answers:
sammy [17]3 years ago
6 0
Hi I think the answer might be 20
marissa [1.9K]3 years ago
4 0

Answer:

(0.5, 1.3)(0.5, 1.3)

Step-by-step explanation:

Given equations are:

As we can see that the given equations are linear equations which are graphed as straight lines on graph. The solution of two equations is the point of their intersection on the graph.

We can plot the graph of both equations using any online or desktop graphing tool.

We have used "Desmos" online graphing calculator to plot the graph of two lines (Picture Attached)

We can see from the graph that the lines intersect at: (0.517, 1.267)

Rounding off both coordinates of point of intersection to nearest tenth we get

(0.5, 1.3)

Hence,

(0.5, 1.3) is the correct answer

Keywords: Linear equations, variables

You might be interested in
Solve f (x)=3x+6 f(300)
sveta [45]

Answer:

f(300)=906

Step-by-step explanation:

f(x)=3x+6\\\\f(300)=3(300)+6\\\\f(300)=900+6\\\\\boxed{f(300)=906}

Hope this helps.

8 0
2 years ago
A manufacturer of computer printers purchases plastic ink cartridges from a vendor. When a large shipment is received, a random
g100num [7]

Answer:

97.4% probability

Step-by-step explanation:

Since there is only two possible outcome of inspecting the catridge : either defective or not, we can solve the problem using the binomial probability distribution (approximated to normal).

To approximate the binomial probability to normal, we find the expected value and the standard deviation of the probability of exactly x sucesses on n repeated trials with p probability

Expected values E(X) = np

Standard deviation √V(X) = √np(1-p)

using the z-score formula (X - μ)/σ, we can solve normally distributed problem.

Where μ is the mean and σ is the standard deviation. The Z-score is is the measure of how much a sample is from the mean. The p-value associated with this z-score which is the probability that the value of the measure is smaller than X can be checked on the z-score table.

FOR THIS QUESTION,

a random sample of 200 cartridges is selected

n = 200

Therefore If there are more than 0.02 × 200 = 4 defective, the sample will be returned.

To determine the approximate probability that a shipment will be returned if the true proportion of defective cartridges in the shipment is 0.05

μ = E(X)

= 0.05 × 200 = 10

σ = √V(X) = √np(1-p)

= √200 × 0.05 × 0.95

= 3.08

This probability is 1 subtracted by the pvalue of Z when X =4

Z = (X - μ)/σ

Z= (4 - 10)/3.08

Z = -1.95

Z = -1.95 has a P-value of 0.026 (on the z-score table)

This means that there is a 1 - 0.026 = 0.974

= 97.4% probability that a shipment will be returned if the true proportion of defective cartridges in the shipment is 0.05.

6 0
3 years ago
A graph is shown below:
Charra [1.4K]

Answer:

The correct answer is actually B. x - 3y < 5

Step-by-step explanation:

Because you must convert the equation to y-intercept form first.

Which makes it y = 1/3x - 1.6

So y = 1.6 and using the slope of 1/3x you can find that x = 5

3 0
3 years ago
Pleaseeeeee help meeee answer number 3,5 and 7 they are hard for me to do
Liula [17]

Answer:

5. 52+56 < 49x -46x

108< 3x

108/3< 3x/3

36

8 0
1 year ago
PLEASE HELP
lisabon 2012 [21]

Step-by-step explanation:

The figure below shows a portion of the graph of the function j\left(x\right) \ = \ 4^{x-2}, hence the average rate of change (slope of the blue line) between the x and x+h is

                     \text{Average rate of change} \ = \ \displaystyle\frac{\Delta y}{\Delta x} \\ \\ \rule{3.7cm}{0cm} = \dsiplaystyle\frac{f\left(x+h\right) \ - \ f\left(x\right)}{\left(x \ + \ h \right) \ - \ x} \\ \\ \\  \rule{3.7cm}{0cm} = \displaystyle\frac{f\left(x + h\right) \ - \ f\left(x\right)}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x+h-2} \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x-2+h} \ - \ 4^{x-2}}{h}

                                                            \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h}\right) \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h} \ - \ 1 \right)}{h}

7 0
1 year ago
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