The decrease is 25% so this means that 22 is 75% of the original number (100% - 25% = 75%)
Divide 22 by 75%:
22/ 0.75 = 29.3
The answer is 29.3
We know that we have to m<span>ake a down payment of $1500 and finance the rest of $20000 at a 1.9% interest rate, making equal monthly payments for 5 years. Our first step to solve this problem would be to convert 5 years into months.
1 year = 12 months
12 * 5 = 60 months
Therefore, in 5 years there are 60 months.
Now lets solve this problem step by step.
Subtract the down payment from $20,000
</span>$20000-$1500=$18500
Multiply the remaining number by the interest rate.
$18500 *1.9 = $35150
Divide 35150 by number of months in 5 years (60)
$35150 / 60 = $585
<span>Therefore, you have to pay $585 per month. </span>
Answer:
98
Step-by-step explanation:
f(x) = 10x² + 8
= 10(-3)² + 8
= 10 (9) + 8
= 90 + 8
= 98
Answer:
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.
Step-by-step explanation:
Previous concepts
The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

Solution to the problem
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.
The answer will be C. OR 3. 11−<span>13<span>i</span></span>