PT=x+2, TR=y, QT=2x, TS=y+3
1 answer:
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Answer: We support the null hypothesis.
Step-by-step explanation:
Given : The purpose of the study was to determine whether the mean weekly number of hours that Internet users in that age group spend online differs from the mean for Internet users in general which is 12.50 hours.
The set of hypothesis for the given claim :-
A 95% confidence interval for the mean weekly number of hours that Internet users in that age group spend online was calculated to be (11.439 , 12.577).
Since 12.50 contained in the 95% confidence interval (11.439 , 12.577).
Therefore, we support the null hypothesis.
So the final conclusion will be, we have evidence to support the claim that Internet users in that age group spend online differs from the mean for Internet users in general which is 12.50 hours.
Answer:
Each students will get 3 tickets and 2 brownies .
Step-by-step explanation:
Given as :
The total number of tickets issued for the school dance = 64
The number of brownies ordered for refreshment table = 96
Let the number of tickets given to each student = x
And The number of brownie given to each student = y
Now,
According to question
The tickets and brownies is distributed equally among students
So , Now, consider the tickets and brownies = n
Or, -
= 1
Or, Taking LCM we get
= 1
Or, = 1
∴ n = 192
Now,
The number of tickets given to each student = x =
I.e x = 3
And The number of brownie given to each student = y =
I.e y = 2
Hence Each students will get 3 tickets and 2 brownies . Answer