What you do is you distribute the 5.
So your answer would be 5x+15
The inequality for this situation is given by 50 + p > 85
<h3>What is an
inequality?</h3>
An inequality is an expression that shows the relationship between two or more numbers and variables.
Let p represent number of pages from Monday to Friday.
Jerome wants to have read at least 85 pages by the end of the day on Friday, hence:
50 + p > 85
The inequality for this situation is given by 50 + p > 85
Find out more on inequality at: brainly.com/question/24372553
Answer:
5.5%
Step-by-step explanation:
To find the interest rate, use the equation: I = prt
I = Interest = $6,600
p = principal = $15,000
r = rate = unknown
t = time = 8 years
Now plug the numbers into the equation.
6,600 = 15,000 * r * 8
6,600 = 120,000 * r
Now isolate the variable by dividing both sides of the equation by 120,000.
0.055 = r
Now change the rate to a percent by moving the decimal point 2 digits to the right.
5.5% = r OR r = 5.5%
Answer:
Hello...... here is a solution :
1 -
Hello:
the equation of "m" is : y = ax+b
the slope is a : a×(- 2/3) = -1......( perpendicular to a line : y=-2/3x+6 when the slope is -2/3 )
a = 3/2
the line " n" that passes through (4, - 3) and parallel to line "m" :
when the slope is 3/2 ( same slope )
the equation in slope-intercept form of the line" n" is :
y – (-3)= (3/2)(x – 4)
Answer: ![3x^2y\sqrt[3]{y}\\\\](https://tex.z-dn.net/?f=3x%5E2y%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C)
Work Shown:
![\sqrt[3]{27x^{6}y^{4}}\\\\\sqrt[3]{3^3x^{3+3}y^{3+1}}\\\\\sqrt[3]{3^3x^{3}*x^{3}*y^{3}*y^{1}}\\\\\sqrt[3]{3^3x^{2*3}*y^{3}*y}\\\\\sqrt[3]{\left(3x^2y\right)^3*y}\\\\\sqrt[3]{\left(3x^2y\right)^3}*\sqrt[3]{y}\\\\3x^2y\sqrt[3]{y}\\\\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27x%5E%7B6%7Dy%5E%7B4%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B3%2B3%7Dy%5E%7B3%2B1%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B3%7D%2Ax%5E%7B3%7D%2Ay%5E%7B3%7D%2Ay%5E%7B1%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B2%2A3%7D%2Ay%5E%7B3%7D%2Ay%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B%5Cleft%283x%5E2y%5Cright%29%5E3%2Ay%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B%5Cleft%283x%5E2y%5Cright%29%5E3%7D%2A%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C3x%5E2y%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C)
Explanation:
As the steps above show, the goal is to factor the expression under the root in terms of pulling out cubed terms. That way when we apply the cube root to them, the exponents cancel. We cannot factor the y term completely, so we have a bit of leftovers.
