Name the focus of y = 0.6x^2.

1 answer:

4 0

Parabola
remember that
parabola equation is
4p(y-k) =(x-h)^2 for a verticl parabola
p=distance from vertex to focus and from vertex to directix
solve for p, k, h

y=0.6x^2

4p(y-0)=(x-0)^2
divide both sides by 4p
(y-0)=1/4p times (x-0)^2
y=0.6x^2

1/(4p)=0.6
find p
multiply 4p
1=2.4p
divide 2.4
1/2.4=p
h=0,k=0
vertex=0,0
opens up so go up to find focus
(0,0)
0+1/2.4=1/2.4
focus is at (0,1/2.4)

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$=-1\frac{1}{2}$

Step-by-step explanation:

Given the following question:

$-3\frac{3}{4} \div2\frac{1}{2}$

In order to find the answer, we first convert the mixed numbers into improper fractions. Then we use KCF (Keep, Change, Flip) and solve.

$-3\frac{3}{4} \div2\frac{1}{2}$
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Hope this helps.