Question

Name the focus of y = 0.6x^2.

Answer 1

Parabola
remember that
parabola equation is
4p(y-k) =(x-h)^2 for a verticl parabola
p=distance from vertex to focus and from vertex to directix
solve for p, k, h

y=0.6x^2

4p(y-0)=(x-0)^2
divide both sides by 4p
(y-0)=1/4p times (x-0)^2
y=0.6x^2

1/(4p)=0.6
find p
multiply 4p
1=2.4p
divide 2.4
1/2.4=p
h=0,k=0
vertex=0,0
opens up so go up to find focus
(0,0)
0+1/2.4=1/2.4
focus is at (0,1/2.4)