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borishaifa [10]
3 years ago
8

Name the focus of y = 0.6x^2.

Mathematics
1 answer:
Aleks04 [339]3 years ago
4 0
Parabola
remember that
parabola equation is
4p(y-k) =(x-h)^2 for a verticl parabola
p=distance from vertex to focus and from vertex to directix
solve for p, k, h

y=0.6x^2

4p(y-0)=(x-0)^2
divide both sides by 4p
(y-0)=1/4p times (x-0)^2
y=0.6x^2

1/(4p)=0.6
find p
multiply 4p
1=2.4p
divide 2.4
1/2.4=p
h=0,k=0
vertex=0,0
opens up so go up to find focus
(0,0)
0+1/2.4=1/2.4
focus is at (0,1/2.4)

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You mean -2x+5y=20 if it was that's how you do it
so if you're finding the x intercept the y will turn to 0 why because you're only looking for x their's no need for y
so it will be -2x+0=20
-2x=20 if it's multiplication then you change it to division
-2x/-2=20/-2
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