Answer:
p value = 0.3122
Step-by-step explanation:
Given that Pedro thinks that he has a special relationship with the number 3. In particular,
Normally for a die to show 3, probability p = 
Or proportion p = 0.1667
Pedro claims that this probability is more than 0.1667

where P is the sample proportion.
b) n=30 and 
Mean difference = 
Std error for proportion = 
Test statistic Z = p difference/std error = 0.4894
p value = 0.3122
p >0.05
So not significant difference between the two proportions.
Answer:
<em>Part A: </em>
<em>c = 1.15p</em>
<em>c(2) = $2.30</em>
<em>Part B: </em>
<em>c = 0.90p</em>
Part B:
Step-by-step explanation:
<u>Linear Models</u>
Candy's Sweets Company charges $1.15 per pound to ship candy. This represents a proportional relationship between the pounds of candy and the cost.
Part A: If each pound costs $1.15, then p pounds cost $1.15p. Then the equation of the cost c is:
c = 1.15p
The cost of shipping p=2 pounds of candy is:
c = 1.15*2 = 2.30
c = $2.30
Part B: When the company reduces the cost by $0.25 per pound, the new unit cost is $1.15 - $0.25 = $0.90 per pound.
The new equation to determine the total cost for p pounds of candy is:
c = 0.90p
1. Find the H.C.F. of 4x2y3 and 6xy2z.
Solution:
The H.C.F. of numerical coefficients = The H.C.F. of 4 and 6.
Since, 4 = 2 × 2 = 22 and 6 = 2 × 3 = 21 × 31
Therefore, the H.C.F. of 4 and 6 is 2
Step-by-step explanation:
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