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Delvig [45]
3 years ago
12

Determine the value of x.

Mathematics
1 answer:
Furkat [3]3 years ago
7 0
The answer to x is 30 because if you do x+2x+3x=180 you can isolate for x
6x=180
x=180/6
x=30
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Prove the following identity true. Show work.
yulyashka [42]

Answer:

The  Pythagorean identity states that

\sin^2 t + \cos^2 t = 1

Using that we can rewrite the left denominator as:

1 - \sin^2 t

Which can be factored as

(1 - \sin t)(1+ \sin t)

The numerator we can expand as:

(1 - \sin t)(1 - \sin t)

On the right hand side, let's multply numerator and denominator with (1 - sin t):

The total formula then becomes:

\dfrac{(1-\sin t)(1-\sin t)}{(1 - \sin t)(1 + \sin t)} = \dfrac{(1-\sin t)(1 - \sin t)}{(1+\sin t)(1 - \sin t)}

There you go... left and right are equal.

3 0
3 years ago
Read 2 more answers
Plz help!!! I’ll give 10 points to the first person to give me a correct answer...I need to get my grade up before the end of th
Lilit [14]

Answer:

A= 30

B= 60

C= 90

Step-by-step explanation:

A is already shown.

B has a right angle making it 90 degrees.

A triangle is 180 degrees 30+90= 120

180-120=60

3 0
3 years ago
Identify the properties used for the first two steps in simplifying 6ab2 + 4a2b – 3ab2 + 3a2b – 2a2b2.
Kryger [21]
The expression 6ab^2+4a^2b-3ab^2+3a^2b-2a^2b^2 has two similar pairs of <span>conjunctions.
</span>
1. Rewrite this expression as
6ab^2+4a^2b-3ab^2+3a^2b-2a^2b^2=
=(6ab^2-3ab^2)+(4a^2b+3a^2b)-2a^2b^2
and then 
2. add the similar <span>conjunctions
</span><span>
</span><span>(6ab^2-3ab^2)+(4a^2b+3a^2b)-2a^2b^2=3ab^2+7a^2b-2a^2b^2.</span><span>
</span><span />

3 0
4 years ago
Read 2 more answers
Can you please help formate this problem
vovangra [49]
Take another picture

5 0
3 years ago
Please help!
leva [86]

longer congruent sides = 6-0 OR 4-(-2) = 6units

perimeter= 3.6×2 + 6×2 = 19.2units

height of parallelogram= 2-(-1) = 3 units

area= 3×6 = 18unit^2

4 0
4 years ago
Read 2 more answers
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