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Neporo4naja [7]
3 years ago
13

Can someone help me? it is going to be greatly appreciated <3

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
8 0
6/11
________________
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Water flows through a pipe at a rate of 0.12 litres per second.
katrin2010 [14]

Answer:

250 seconds

Step-by-step explanation:

(0.12/1 = 30/x)

0.12x = 30

x = 250

8 0
3 years ago
Write an equation of the line with slope 2/3 that goes through the point (- 2, 5) .
Nady [450]

Answer:

y - 5 = (2/3)(x + 2)

Step-by-step explanation:

Use the point-slope formula y - k = m(x - h), recognizing that h = -2, y = 5 and m = 2/3:

y - 5 = (2/3)(x + 2)

5 0
4 years ago
If a+b = -0.5 and ab = -2 , then what is 4a^3+9b?
m_a_m_a [10]

Answer:

pls be more cleare

Step-by-step explanation:

type the question properly and clearly

5 0
3 years ago
What is the product of 7.68 and 3.92?
nataly862011 [7]

Answer:

30.1056

Step-by-step explanation:

dude just multiply it

duh.... ☠

3 0
3 years ago
The mean salary of actuaries is LaTeX: \mu=\$100,000????=$100,000 and the standard deviation is LaTeX: \sigma=\$36,730????=$36,7
krek1111 [17]

Answer:

The lower limit of 95% confidence interval is 99002.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = $100,000

Sample mean, \bar{x} = $111,000

Sample size, n = 36

Alpha, α = 0.05

Population standard deviation, σ = $36,730

First, we design the null and the alternate hypothesis

H_{0}: \mu = \$100,000\\H_A: \mu \neq \$100,000

We have to find the lower limit of the 95% confidence interval.

95% Confidence interval:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

111000 \pm 1.96(\dfrac{36730}{\sqrt{36}} )\\\\ = 111000 \pm 11998.4667 \\= (99001.5333,122998.4667)\\ \approx (99002,122999)

The lower limit of 95% confidence interval is 99002.

6 0
4 years ago
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