Answer:
1) ΔACD is a right triangle at C
=> sin 32° = AC/15
⇔ AC = sin 32°.15 ≈ 7.9 (cm)
2) ΔABC is a right triangle at C, using Pythagoras theorem, we have:
AB² = AC² + BC²
⇔ AB² = 7.9² + 9.7² = 156.5
⇒ AB = 12.5 (cm)
3) ΔABC is a right triangle at C
=> sin ∠BAC = BC/AB
⇔ sin ∠BAC = 9.7/12.5 = 0.776
⇒ ∠BAC ≈ 50.9°
4) ΔACD is a right triangle at C
=> cos 32° = CD/15
⇔ CD = cos32°.15
⇒ CD ≈ 12.72 (cm)
Step-by-step explanation:
check the picture below.
it cannot be -1, because is a seconds amount after moving.
For the first one, we add 2.7 to both sides to get x≥13. Next, we divide both sides by -0.84 to get x≥ 168/-0.84. SInce we multiplied or divided by a negative number, we switch the sign around and end up with x≥200
40(60/100) 4(6/10) =24/10 = 2.4
