3 years ago

What is the solution to the system of equations 2x + 3y = 40 and y = x +10?oy - y - 12

Mathematics

1 answer:

marissa [1.9K]3 years ago

4 0

Answer:

hope this is correct

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Triangle DNO has vertices at D(5, 8), N(– 3, 10), and O(– 3, 6). If vertex D is translated 4 units to the right, the best name f

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Using distance between two points to find the lengths of the edges of the triangle, the correct option is:

b. Isosceles

The distance between two points, $(x_1,y_1)$ and $(x_2,y_2)$ , is given by:

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Vertex D is translated 4 units to the right is (9,8).

The lengths of the edges are:

$DN = \sqrt{(9 - (-3))^2 + (8 - 10)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}$

$DO = \sqrt{(9 - (-3))^2 + (8 - 6)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}$

$NO = \sqrt{(-3 - (-3))^2 + (10 - 6)^2} = \sqrt{0^2 + 4^2} = 4$

Two edges of the same length, hence, it is an isosceles triangle, given by option b.

You can learn more about distance between two points at brainly.com/question/18345417

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aalyn [17]

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Step-by-step explanation:

angle A = 40

angle B = 60

angle C = we don't know.

A + B + C = 180

C = 180 - A - B

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3 years ago

What is the solution to the system of equations 2x + 3y = 40 and y = x +10?oy - y - 12​

What is the solution to the system of equations 2x + 3y = 40 and y = x +10?oy - y - 12