Question

2x/x2-25=10/x2-25 - 4/x+5

Answer 1

Hello,

x²-25≠0==>x≠5 and x≠-5

$\dfrac{2x}{x^2-25}= \dfrac{10}{x^2-25}- \dfrac{4}{x+5} \\ \dfrac{2x}{x^2-25}= \dfrac{10}{x^2-25}- \dfrac{4(x-5)}{(x+5)(x-5)} \\ 2x=10-4x+20\\ 6x=30\\ x= 5$