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Finger [1]
3 years ago
9

Does anyone know how to do this ? I do not understand how to do this project

Mathematics
1 answer:
deff fn [24]3 years ago
3 0
So, basically you have to get a data set, which you can almost freely choose the subject of. Then, you must get a visual representation, like a bar graph, with all of the data that you use. Make sure you label!! Lastly, all you have to do is answer all of the questions in part 3. Those include numbers 1, 2, 4, and 5. for number 3, you are able to choose between letters a and b, depending on either you or your subject. Then you just turn it in. Sorry if it was a vague description, but it's a pretty straightforward project. Hope it helped a little bit!!
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1) factor the denominators: 2b/(b-1)2 - 2/ (b-1)2
2) MAKE SURE YOU HAVE A COMMON DENOMINATOR
3) combine the numerators: 2b-2/(b-1)2
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Answer:

20. AB = 42

21. BC = 28

22. AC = 70

23. BC = 20.4

24. FH = 48

25. DE = 10, EF = 10, DF = 20

Step-by-step explanation:

✍️Given:

AB = 2x + 7

BC = 28

AC = 4x,

20. Assuming B is between A and C, thus:

AB + BC = AC (Segment Addition Postulate)

2x + 7 + 28 = 4x (substitution)

Collect like terms

2x + 35 = 4x

35 = 4x - 2x

35 = 2x

Divide both side by 2

17.5 = x

AB = 2x + 7

Plug in the value of x

AB = 2(17.5) + 7 = 42

21. BC = 28 (given)

22. AC = 4x

Plug in the value of x

AC = 4(17.5) = 70

✍️Given:

AC = 35 and AB = 14.6.

Assuming B is between A and C, thus:

23. AB + BC = AC (Segment Addition Postulate)

14.6 + BC = 35 (Substitution)

Subtract 14.6 from each side

BC = 35 - 14.6

BC = 20.4

24. FH = 7x + 6

FG = 4x

GH = 24

FG + GH = FH (Segment Addition Postulate)

4x + 24 = 7x + 6 (substitution)

Collect like terms

4x - 7x = -24 + 6

-3x = - 18

Divide both sides by -3

x = 6

FH = 7x + 6

Plug in the value of x

FH = 7(6) + 6 = 48

25. DE = 5x, EF = 3x + 4

Given that E bisects DF, therefore,

DE = EF

5x = 3x + 4 (substitution)

Subtract 3x from each side

5x - 3x = 4

2x = 4

Divide both sides by 2

x = 2

DE = 5x

Plug in the value of x

DE = 5(2) = 10

EF = 3x + 4

Plug in the value of x

EF = 3(2) + 4 = 10

DF = DE + EF

DE = 10 + 10 (substitution)

DE = 20

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