Ask question

Ask question

All categories

3 years ago

9

Does anyone know how to do this ? I do not understand how to do this project

1 answer:

deff fn [24]3 years ago

3 0

So, basically you have to get a data set, which you can almost freely choose the subject of. Then, you must get a visual representation, like a bar graph, with all of the data that you use. Make sure you label!! Lastly, all you have to do is answer all of the questions in part 3. Those include numbers 1, 2, 4, and 5. for number 3, you are able to choose between letters a and b, depending on either you or your subject. Then you just turn it in. Sorry if it was a vague description, but it's a pretty straightforward project. Hope it helped a little bit!!

You might be interested in

Dont answer this question if you dont know the answer

nekit [7.7K]

Answer:

C

Step-by-step explanation:

sin = 5/13

cos = 12/13

tan = 5/12

3 0

3 years ago

2/3a = -24<br><br> Please solve the equation and show how you got the answer! (:

devlian [24]

You have to isolate the (a) so you multiply the 2/3 by 3/2 and you have to do that to the right side. So -24 times 3/2 equals to -36. Therefore, a=-36.

3 0

3 years ago

Find the quotient of 2,300 and (0.4 · 10^-8). In your final answer, include all of your calculations.

Alex777 [14]

Answer:

5.75x10^11

Step-by-step explanation:

quotient of 2,300 and (0.4x10^-8) is

2,300 ÷ (0.4x10^-8)

2300 = 2.3x10^3

We now have

2.3x10^3 / 0.4x10^-8

= (2.3/0.4) x ( 10^(3 - (-8))

= 5.75 x (10^(3+8))

= 5.75 x (10^11)

= 5.75x10^11

Please mark brainliest if helpful. Thanks

8 0

3 years ago

Convert the Cartesian equation x^2 + y^2 = 16 to a polar equation.

RideAnS [48]

Answer:

Problem 1: $r=4$

Problem 2: $r=-2\sin(\theta)$

Problem 3: $r\sin(\theta)=3$

Step-by-step explanation:

Problem 1:

So we are going to use the following to help us:

$x=r \cos(\theta)$

$y=r \sin(\theta)$

$\frac{y}{x}=\tan(\theta)$

So if we make those substitution into the first equation we get:

$x^2+y^2=16$

$(r\cos(\theta))^2+r\sin(\theta))^2=16$

$r^2\cos^2(\theta)+r^2\sin^2(\theta)=16$

Factor the $r^2$ out:

$r^2(\cos^2(\theta)+\sin^2(\theta))=16$

The following is a Pythagorean Identity: $\cos^2(\theta)+\sin^2(\theta)=1$ .

We will apply this identity now:

$r^2=16$

This implies:

$r=4 \text{ or } r=-4$

We don't need both because both of include points with radius 4.

Problem 2:

$x^2+y^2+2y=0$

$(r\cos(\theta))^2+(r\sin(\theta))^2+2(r\sin(\theta))=0$

$r^2\cos^2(\theta)+r^2\sin^2(\theta)+2r\sin(theta)=0$

Factoring out $r^2$ from first two terms:

$r^2(\cos^2(\theta)+\sin^2(\theta))+2r\sin(\theta)=0$

Apply the Pythagorean Identity I mentioned above from problem 1:

$r^2(1)+2r\sin(\theta)=0$

$r^2+2r\sin(\theta)=0$

or if we factor out r:

$r(r+2\sin(\theta))=0$

$r=0 \text{ or } r=-2\sin(\theta)$

r=0 is actually included in the other equation since when theta=0, r=0.

Problem 3:

$y=3$

$r\sin(\theta)=3$

8 0

4 years ago

the volume of a cylinder is 600 pi in3. The height of the cylinder is 6in. I have to calculate the radius of the cylinder

galina1969 [7]

<span>the volume of a cylinder is 80pi cubic inches; if the radius is 4 in. find the height</span>

7 0

3 years ago