Answer:
Explanation contains the proof.
Step-by-step explanation:
.
.
We want to show that
. So we are asked to show that there exist integer ![n \text{ such that } 8n=ab+1 \text{ or 8n-1=ab](https://tex.z-dn.net/?f=n%20%5Ctext%7B%20such%20that%20%7D%208n%3Dab%2B1%20%5Ctext%7B%20or%208n-1%3Dab)
So what is
?
.
.
So back to
....
![ab](https://tex.z-dn.net/?f=ab)
![=(8k+5)(8m+5)](https://tex.z-dn.net/?f=%3D%288k%2B5%29%288m%2B5%29)
(I use foil to get this)
Factoring out 8 gives us:
![=8(8km+5k+5m)+25](https://tex.z-dn.net/?f=%3D8%288km%2B5k%2B5m%29%2B25)
Now I could have factored some 8's out of 25. There are actually three 8's in 25 with a remainder of 1.
![=8(8km+5k+5m+3)+1](https://tex.z-dn.net/?f=%3D8%288km%2B5k%2B5m%2B3%29%2B1)
We have shown that there is integer
.
The integer I found that is n is 8km+5k+5m+3.
Therefore
.
//
It’s 2 because it says that three teaspoons equal to one tablespoon so
6/3= 2
x equals negative 9 i think
Step-by-step explanation:
let y = x+5/4
Interchanging x and y , we get ;
x = y+5/4
or, 4x = y+5
or, 4x-5 = y
or, g(x) -1 = 4x-5