I couldn’t really understand the question but i did 4squared + 3r(1) - 7(1)squared and i got -33 + 3r
First triangle=bxh/2
=3x4/2
=6in squared
rectangle=l x w
=3 x 10
=30in squared
trapezoid=3+5x2/2
=8in squared
6 + 30 + 8
=44 in squared
If we take the square of x and square of y and then subtract them:
(csc t)²-(cot t)²=1 ( this eq. gets from basic identity
x²-y²=1......a 1+cot²x=csc²x)
equation 'a' represent the equation of hyperbola which is (x²/a²)-(y²/b²) =1 with given conditions( a=1,b=1)
So, option D is correct
8ft is the length of the rope on the outside of the tent. I hope its right!