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2 years ago

Please show work for both problems

Mathematics

1 answer:

kirill [66]2 years ago

6 0

Answer:

3) x = 15; 95 and 85 4) x = 12; 98 for both angles

Step-by-step explanation:

2x + 65 + 3x + 40 = 180 Set the equations equal to 180

5x + 105 = 180 Combine like terms

- 105 - 105 Subtract 105 from both sides

5x = 75 Divide both sides by 5

x = 15

Plug 15 into both equations

2(15) + 65 = 95

3(15) + 40 = 85

4) 5x + 38 = 9x - 10 Set the equations equal to each other

- 5x - 5x Subtract 5x from both sides

38 = 4x - 10

+ 10 + 10 Add 10 to both sides

48 = 4x Divide both sides by 4

12 = x

Plug 12 into both equations

5(12) + 38 = 98

9(12) - 10 = 98

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3 years ago

A street light is at the top of a 25 ft pole. A 4 ft tall girl walks along a straight path away from the pole with a speed of 6

Burka [1]

Answer:

Tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

Step-by-step explanation:

Given : In the figure attached, Length of girl EC = 4 ft

Length of street light AB = 25 ft

Girl is moving away from the light with a speed = 6 ft per sec.

To Find : Rate ( $\frac{dw}{dt}$ ) of the tip (D) of the girl's shadow (BD) moving away from th

light.

Solution : Let the distance of the girl from the street light is = x feet

Length of the shadow CD is = y feet

Therefore, $\frac{dx}{dt}=6$ feet per sec. [Given]

In the figure attached, ΔAFE and ΔADE are similar.

By the property of similar triangles,

$\frac{x}{21}=\frac{x+y}{25}$

25x = 21(x + y)

25x = 21x + 21y

25x - 21x = 21y

4x = 21y

y = $\frac{4x}{21}$

Now we take the derivative on both the sides,

$\frac{dy}{dt}=\frac{4}{21}\times \frac{dx}{dt}$

= $\frac{4}{21}\times 6$

= $\frac{8}{7}$

≈ 1.14 ft per sec.

Since w = x + y

Therefore, $\frac{dw}{dt}= \frac{dx}{dt}+\frac{dy}{dt}$

$\frac{dw}{dt}=6+1.14$

= 7.14 ft per sec.

Therefore, tip of the shadow of the girl is moving with a rate of 7.14 feet per sec.

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3 years ago

Solve for the variable c in this equation a(c + b) = d

noname [10]

Multiply everything in the parenthesis by a.

ac + ab = d

Subtract ab from both sides.

ac = d - ab

Divide a on both sides.

c = d - ab / a

Hope this helps!

3 0

3 years ago