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Mazyrski [523]
2 years ago
15

Jaron walked 15 blocks north and then 3 blocks west to school. Marisol walked 3 blocks east and then 15 blocks south to school.

Write an expression to show that each traveled the same distance.
Mathematics
1 answer:
Svet_ta [14]2 years ago
5 0

Answer:

sqrt(15² + 3²) = sqrt(15² + 3²)

Step-by-step explanation:

Using Pythagoras:

15 blocks North = 15 blocks south (direction opposite to each other)

3 blocks west = 3 blocks east (directions opposite to each other)

Hence distance traveled (d) :

JARON

D = sqrt(15² + 3²)

MARISOL:

D = sqrt(15² + 3²)

Hence ;

sqrt(15² + 3²) = sqrt(15² + 3²)

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Drew drives his car and Rachel drives her truck in the same direction on the highway at constant speeds for 3.25 hours. During t
never [62]

Answer:

After 4.5 hours of driving at the same constant speeds, Drew and Rachel are 6.5 miles apart.

Hope This Helps :)

4 0
3 years ago
Order the set of numbers from least to greatest<br><br>3/5, 3/10, 2/7, 1/4
Mkey [24]
3/10 2/7 1/4 3/5 that is least to greatest
8 0
3 years ago
10 squared divided by 2c -b + 3a<br><br> A = 1/3<br> B= 9<br> C = 5
Svet_ta [14]

Answer:

50

Step-by-step explanation:

Figure out all variables

100/(2x5= 10)-9+(3x.33=1)

100/10-9+1

100/2

50

8 0
3 years ago
A quality control expert at Glotech computers wants to test their new monitors. The production manager claims they have a mean l
tankabanditka [31]

Answer:

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = 0.0087

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the mean of the Population = 95

Given that the standard deviation of the Population = 5

Let 'X' be the random variable in a normal distribution

Let X⁻ = 96.3

Given that the size 'n' = 84 monitors

<u><em>Step(ii):-</em></u>

<u><em>The Empirical rule</em></u>

         Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }

        Z = \frac{96.3 - 95}{\frac{5}{\sqrt{84} } }

       Z = 2.383

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

    P(X⁻ ≥ 96.3) = P(Z≥2.383)

                      =  1- P( Z<2.383)

                      =  1-( 0.5 -+A(2.38))

                      = 0.5 - A(2.38)

                     = 0.5 -0.4913

                    = 0.0087

<u><em>Final answer:-</em></u>

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = 0.0087

3 0
2 years ago
Photo attached. Thanks in advance!
jonny [76]
A zero in front of the x would make this a difference of two perfect squares. All of the other option would interfere by adding another term.
7 0
3 years ago
Read 2 more answers
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