Solution:
As given Rectangle ABCD is reflected over the y- axis.
When a shape or geometrical figure is reflected through a line it's distance that is distance of image from line and distance of Pre-image from that line is always same.Also perpendicular distance of vertices of any polygon that is considered for reflection has same distance from that line after reflection and before reflection.
Suppose the coordinate of A be (x,y) and considering Rectangle A B CD lie in first quadrant then when it is reflected through y - axis that is through the line x=0, it's new coordinate will become A' (-x,y).
If rectangle is in second quadrant having Vertices that is vertices of A (-x,y) then reflected over line that is x=0,→ y axis then Vertices of A' (x,y).
If rectangle is in third quadrant having Vertices that is vertices of A (-x,-y) then reflected over line that is x=0,→ y axis then Vertices of A' (x,-y).
If rectangle is in fourth quadrant having Vertices that is vertices of A (x,-y) then reflected over line that is x=0,→y axis then Vertices of A' (-x,-y).
Divide each term by x and simplify.
(Ok so I don’t make it confusing the first part after “F=“ will be on top The I’ll put the bottom part below oh btw the top and bottom r negative so put the negative sign in front of the fraction)
F= - 21fx+x√x-2x-3(top of fraction)
F=-x^2(bottom of fraction)
Answer:
See Below
Step-by-step explanation:
We are given 3 equations.
3x + 8
5x - 20
and
5x + 4y
First lets solve for x using the first two
3x + 8 = 5x -20
Move the variables to one side
3x + 8 = 5x -20
-3x -3x
8 = 2x -20
+20 +20
28 =2x
28/2 =2x /2
14 = x
Now we have x = 14
Lets plug this into the second equation to solve for the angle
3(14) + 8
42 + 8 = 50
5(14) - 20
70 - 20 =50
Now, lets plug the x and the angle into the third equation to find y
5 (14) +4y = 50
70 + 4y = 50
-70 -70
4y = -20
4y/4 = -20/4
y = -5
So now we have:
x = 14
y = -5
and the angle = 50
Hope this helps!
1)a parallelogram is a quadrilateral with opposite sides being parallel so the lines AB must equal CD or otherwise it wouldn't be a parallelogram
2)for a quadrilateral to be proven to be a parallelogram the consecutive angles has to be supplementary which means they add up to 180 or for example you could slice the parallelogram in half down the middle you could piece the two consecutive angles together to make 180 degrees
Answer:
83+11_
Step-by-step explanation:
