The solutions to the given system of equations are x = 4 and y = -9
<h3>Simultaneous linear equations</h3>
From the question, we are to determine the solutions to the given system of equations
The given system of equations are
-8x-4y=4 --------- (1)
-5x-y=-11 --------- (2)
Multiply equation (2) by 4
4 ×[-5x-y=-11 ]
-20x -4y = -44 -------- (3)
Now, subtract equation (3) from equation (1)
-8x -4y = 4 --------- (1)
-(-20x -4y = -44) -------- (3)
12x = 48
x = 48/12
x = 4
Substitute the value of x into equation (2)
-5x -y = -11
-5(4) -y = -11
-20 -y = -11
-y = -11 + 20
-y = 9
∴ y = -9
Hence, the solutions to the given system of equations are x = 4 and y = -9
Learn more on Simultaneous linear equations here: brainly.com/question/26310043
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Given parameters;
Let us solve this problem step by step;
Let us represent Simon's money by S
Kande's money by K
- Simon has more money than Kande
S > K
- if Simon gave Kande K20, they would have the same amount;
if Simon gives $20, his money will be S - 20 lesser;
When Kande receives $20, his money will increase to K + 20
S - 20 = K + 20 ------ (i)
- While if Kande gave Simon $22, Simon would then have twice as much as Kande;
if Kande gave Simon $22, his money will be K - 22
Simon's money, S + 22;
S + 22 = 2(K - 22) ------ (ii)
Now we have set up two equations, let us solve;
S - 20 = K + 20 ---- i
S + 22 = 2(K - 22) ; S + 22 = 2K - 44 ---- ii
So, S - 20 = K + 20
S + 22 = 2K - 44
subtract both equations;
-20 - 22 = (k -2k) + 64
-42 = -k + 64
k = 106
Using equation i, let us find S;
S - 20 = K + 20
S - 20 = 106 + 20
S = 106 + 20 + 20 = 146
Therefore, Kande has $106 and Simon has $146
Answer:
15 weeks
The amount of money is 270
Step-by-step explanation:
You: 60 +14x
Sister: 120+10x
Set them equal to each other
60+14x = 120+10x
Subtract 10x from each side
60+4x= 120
Subtract 60 from each side
4x= 60
Divide by 4
4x/4 = 60/4
x = 15
15 weeks
The amount of money is 120+10*15 = 120+150 = 270
Answer:
X Y
1 5
4/5 4
2/5 2
Step-by-step explanation:
y=5x
We we know y we need to solve for x
X Y
5
4
2
Let y =5
5 = 5x
Divide by 5
5/5 =5x/5
1=x
Let y =4
4 = 5x
Divide by 5
4/5 =5x/5
4/5=x
Let y =2
2 = 5x
Divide by 5
2/5 =5x/5
2/5=x
X Y
1 5
4/5 4
2/5 2
6: -8+4V
8: -9-15V OR -9+(-)15V
10:-17+33V
