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Valentin [98]
3 years ago
5

PLZZZ HELP ME OUT THIS DUE RIGHT NOW AND I FREAKING OUT PLEASE HELP ME P.S YOU HAVE WRITE ANSWERS FOR ALL OF THEM

Mathematics
2 answers:
Levart [38]3 years ago
6 0

Answer:

a then b each have a value work out whether its numbered or distributed on a number line -2 , -1 0 , 1, 2, 3, 4, 5 etc if a is -4 then if 1-a = 1--4 the answer is -5 then when the question ab +1 comes up if b = 3 then ab-1 will be written out again as -4 x 3 -1 = -12-1=-13 etc. etc.

ab+1 is different if a = -4 and b = 3 then ab+1 = -4 x 3 +1 = -12 +1 = -11

its count back for( minus then times) count back for( minus then subtract ) and count back for any subtract and forward for positive add minus

Hope that helps branliest please =)

AnnZ [28]3 years ago
5 0

Answer:

Step-by-step explanation:

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A sample of 11 students using a Ti-89 calculator averaged 31.5 items identified, with a standard deviation of 8.35. A sample of
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Answer:

We reject H₀, with CI = 90 % we can conclude that the mean numbers of times identified with Ti-84 does not exceed that of the Ti-89 by more than 1,80

Step-by-step explanation:

Ti-89 Calculator

Sample mean     x = 31,5

Sample standard deviation   s₂  = 8,35

Sample size        n₂ = 11

Ti-84 Calculator

Sample mean     y = 46,2

Sample standard deviation   s₁  = 9,99

Sample size        n₁ = 12

t(s)  = ( y - x - d ) / √s₁²/n₁ + s₂²/n₂

t(s)  = 12,9 / √(99,8/12) + (69,72/11)

t(s)  = 12,9 / √8,32 + 6,34

t(s)  = 12,9 / 3,83

t(s) = 3,37

Test Hypothesis

Null Hypothesis               H₀      y - x > 1,80

Altenative Hypothesis       Hₐ      y - x ≤ 1,80

We have a t(s) = 3,37

We need to compare with t(c)   critical value for

t(c) α; n₁ +n₂-2            df = 12 +11 -2     df  = 21

If we choose  CI = 95 %    then  α = 5 %   α = 0,05

From t-student table

t(c) = 1,72

t(s) = 3,37

t(s) >t(c)

t(s) is in the rejection region therefore we accept Hₐ with CI = 95 %

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Answer:

128

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they are parralel

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