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Valentin [98]
3 years ago
5

PLZZZ HELP ME OUT THIS DUE RIGHT NOW AND I FREAKING OUT PLEASE HELP ME P.S YOU HAVE WRITE ANSWERS FOR ALL OF THEM

Mathematics
2 answers:
Levart [38]3 years ago
6 0

Answer:

a then b each have a value work out whether its numbered or distributed on a number line -2 , -1 0 , 1, 2, 3, 4, 5 etc if a is -4 then if 1-a = 1--4 the answer is -5 then when the question ab +1 comes up if b = 3 then ab-1 will be written out again as -4 x 3 -1 = -12-1=-13 etc. etc.

ab+1 is different if a = -4 and b = 3 then ab+1 = -4 x 3 +1 = -12 +1 = -11

its count back for( minus then times) count back for( minus then subtract ) and count back for any subtract and forward for positive add minus

Hope that helps branliest please =)

AnnZ [28]3 years ago
5 0

Answer:

Step-by-step explanation:

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X = ?????? Geometry
adelina 88 [10]

Answer:

\boxed{x^2 = 16}

Step-by-step explanation:

Using Tangent Secant theorem:

(x)² = (2)(2+6)

x² = 2(8)

x² = 16

7 0
2 years ago
Which of the following is a monomial???
aleksandrvk [35]
Monomial is a product of numbers and variables in any whole power.
Examples of monomials: 5, y, 2x, 2x⁷, 2xyz, 6x²y¹⁰⁰.
Monomial cannot have log,subtraction or addition, negative power.
x/y=xy⁻¹

So, only monomial here is A.y
7 0
2 years ago
Answer the question on the image <br><br><br><br> ty :P
sattari [20]
Answer : 7 or 7/1

step by step explanation:
6 0
3 years ago
-5+13=k<br><img src="https://tex.z-dn.net/?f=%20-%205%20%2B%2013%20%3D%20k" id="TexFormula1" title=" - 5 + 13 = k" alt=" - 5 + 1
Vikentia [17]
Use the communicative property of addition to switch to order and you get
13 - 5, so the answer is 8, or k = 8

OR

-5 + 13 = k
Combine like terms
8 = k
or
k = 8<span />
5 0
3 years ago
Help me answer this question please
enot [183]

Figure D could be formed from the net.

(bottom right)

-Because-

The net says that the middle shape (the bottom face) is 14 long, and it is 8 tall. So the only option that makes sense is the bottom right!

<em>feel free to mark brainliest! :)</em>

5 0
3 years ago
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