1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).
2. Use formula 
to find the distance from point 
to the line Ax+By+C=0.
The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:
.
3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.
Answer: 
.
The answer is C. 50 in, 48 in, 14 in
In a right triangle, a² + b² = c², where c is the longest side (hypotenuse), a and b are the other two sides.
14² + 48² = 196 + 2304 = 2500
50² = 2500
Answer:
C. 3.3 kg.
Step-by-step explanation:
There are 1000 grams in a kilogram.
So 3,000 g = 3300/1000
= 3.3 kg.
Answer:
0
Step-by-step explanation:
f(x) = 2/5(6 - x)²
f(6) = 2/5[6 - (6)]²
f(6) = 2/5(0)²
f(6) = 0
Answer:
875 ft²
Step-by-step explanation:
Finding area of similar rectangles:
Scale factor = EF : AB
= 25 : 5
= 5 : 1
Area or rectangle EFGH = 875 ft²
