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3 years ago

Help please... and thank you :)

Mathematics

2 answers:

Leviafan [203]3 years ago

6 0

Answer:

The answer is 1

Step-by-step explanation:

Any number to the power of 0 is 1

zzz [600]3 years ago

6 0

Answer:

<h2>1 is the answer.</h2>

Step-by-step explanation:

This is the answer because when you place a number to the 0th power then they are equal to 1. This applies to all numbers and variables.

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Please help with question 8 and explain steps

Ket [755]

2 -> 7; but 7 = 2 * 2 + 3;
3 -> 9; but, 9 = 3 *2 + 3;
4 -> 11; but, 11 = 4 * 2 + 3;
5 -> 13; but, 13 = 5 * 2 + 3;

The rule is : ( your number ) * 2 + 3;

The function rule is f( x ) = 2x + 3.

4 0

2 years ago

What is the slope of a line represented by the equation 2y = x – 4

wariber [46]

Answer:

the Slope is $\frac{x}{2}$

Step-by-step explanation:

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3 years ago

Write two and forty-two thousandths in decimal notation. please

Andru [333]

Answer:

Your answer is 2.042

Step-by-step explanation:

If you want it simplified you can change it to

2.0/2.04.

5 0

2 years ago

What is the area of △FGH to the nearest tenth of a square meter? The image is of a triangle GHF with base GH length 2m, FG is 2.

Gnesinka [82]

First, we are going to use the law of cosines to find the length of the line segment FH:
$FH= \sqrt{2.5^{2}+2^{2}-(2)(2.5)Cos(121)}$
$FH= \sqrt{2.5^{2}+2^{2}-5Cos(121)}$
$FH=3.2$

Next, we are going to use the semi-perimeter formula: $s= \frac{GH+FG+FH}{2}$
$s= \frac{2+2.5+3.2}{2}$
$s= \frac{7.7}{2}$
$s=3.9$

Now that we have the semi-perimeter of our triangle, we can find its area using Heron's formula:
$A= \sqrt{s(s-GH)(s-FG)(s-FH)}$
$A= \sqrt{3.9(3.9-2)(3.9-2.5)(3.9-3.2)}$
$A= \sqrt{3.9(1.9)(1.4)(0.7)}$
$A=2.7m^{2}$

We can conclude that the area of the triangle <span>GHF is 2.7 </span> $m^{2}$ .

3 0

3 years ago

How much work is done on an object if 6 newtons of force are applied to the object and it moves 3 meters?

motikmotik

D. 18 J because it’s the most reasonable answer

7 0

3 years ago

Help please... and thank you :)​

Help please... and thank you :)