Question

Heck I can't leave I should but I can't---At a local pet store, Shirley noticed that about four out of five customers who bought pets chose goldfish. Shirley wants to know the estimated probability that three randomly selected customers buying pets would not buy goldfish. How could Shirley design a simulation for this scenario?
A.
She could roll a six-sided die three times. On the die, numbers 1 to 3 represent customers who buy goldfish and 4 to 6 represent customers who don’t buy goldfish.
B.
She could spin a spinner divided into nine equal sections three times. On the spinner, four sections represent customers who buy goldfish and five sections represent customers who do not buy goldfish.
C.
She could spin a spinner divided into five equal sections three times. On the spinner, four sections represent customers who buy goldfish and one section represents customers who do not buy goldfish.
D.
She could use a random number generator to generate a set of three numbers from 0 to 9. The numbers 0 to 4 represent customers who buy goldfish, and 5 to 9 represent customers who do not buy goldfish.
E.
She could use a number generator to generate a set of five numbers from 0 to 3. The numbers 0 to 2 represent customers who buy goldfish, and 3 represents customers who do not buy goldfish.

Answer 1

Answer:

C. She could spin a spinner divided into five equal sections three times. On the spinner, four sections represent customers who buy goldfish and one section represents customers who do not buy goldfish.

Step-by-step explanation:

We are told that four out of five customers who bought pets chose goldfish.

Thus;

P(those who bought pets also chose gold fish) = 4/5

Therefore;

P(those who bought pets but do not buy gold fish) = 1 - (4/5) = 1/5

Now, she wants to know the estimated probability that three randomly selected customers buying pets would not buy goldfish.

The probability we have is 1/5.

Therefore,to accommodate the 3 randomly selected customers, we have to multiply the numerator and denominator for each probability by 3.

Thus;

P(those who bought pets also chose gold fish) = 4/5 × 3/3 = 12/15

P(those who bought pets but do not buy gold fish) = 1/5 × 3/3 = 3/15

Looking at the new probabilities, the simulation she can use is to divide a spinner into five equal sections three times so that for each section, we can have the probability of 1/5 and 4/5.

Thus, option C is correct.