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serg [7]
3 years ago
7

write the program or pseudocode algorithm that computes the product and average of three integers and display the results​

Computers and Technology
1 answer:
sweet-ann [11.9K]3 years ago
7 0

<u>Answer:</u>

<u><em>Algorithm: </em></u>

<em>Step 1: </em><em>Begin </em>

<em>Step 2: </em><em>Obtain the inputs – all the three integers </em>

<em>Step 3: </em><em>Calculate product using the formula “a*b*c” </em>

<em>Step 4: </em><em>Calculate sum and then with the help of sum calculate the average </em>

<em>Step 5: </em><em>Print the value of product and average </em>

<em>Step 6: </em><em>End </em>

<u>Explanation:</u>

<u><em>Program: </em></u>

<em>#include<stdio.h> </em>

<em>int main () { </em>

<em>    int a, b, c; </em>

<em>    printf(""Enter three numbers: ""); </em>

<em>    scanf(""%d %d %d"", &a, &b, &c); </em>

<em>    int sum = a + b + c; </em>

<em>    int product = a * b * c; </em>

<em>    float avg = sum / 3.0; </em>

<em>    printf(“Product = %d”, product”);  </em>

<em>    printf(""Sum = %d, Average = %f"", sum, avg); </em>

<em>    return 0; </em>

<em>} </em>

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Answer:

The program to this question as follows:

Program:

def isEvenPositiveInt(x): #defining method isEvenPositiveInt

   if x>0: #checking number is positive or not

       if x%2==0: #check true condition

           return True #return value True

       else:

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print(isEvenPositiveInt(-24)) #calling method and print return value

print(isEvenPositiveInt(23)) #calling method and print return value

Output:

True

False

False

Explanation:

In the above Python program, a method "isEvenPositiveInt" is defined, that accepts a variable "x" as its parameter, inside the method a conditional statement is used, which can be described as follows:

  • In the if block the condition "x>0" is passed, that check value is positive, if this condition is true, it will go to another if block.
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4 years ago
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