Router? Modem? I have no ideas outside of those.
Wipe off the hard drive with a software eraser but it won't be quick and won't work on defective disks
In order to derive the probability of stock outs, divide the total value of the stock outs by the number of requests demanded. The resulting figure must then be multiplied by 100.
<h3>What is a stock out?</h3>
In business, a stock out refers to a condition where in a certain item or items are no longer available in stock.
The formula can be sated simply as:
Probability of Stock outs = (No of stock outs/ number of demand requests) x 100
Thus Number of Stock outs = Total probability of stock outs * total number of demand requests.
<h3>What is the formula for the Total Cost?</h3>
The formula for Total Cost is given as:
Total Fixed Cost + Total Variable Cost;
TC = TFC + TVC
Learn more about stock outs at:
brainly.com/question/16209393
#SPJ1
Answer:
print("Let's play Silly Sentences!")
print(" ")
name=input("Enter a name: ")
adj1=input("Enter an adjective: ")
adj2=input("Enter an adjective: ")
adv=input("Enter an adverb: ")
fd1=input("Enter a food: ")
fd2=input("Enter another food: ")
noun=input("Enter a noun: ")
place=input("Enter a place: ")
verb=input("Enter a verb: ")
print(" ")
print(name + " was planning a dream vacation to " + place + ".")
print(name + " was especially looking forward to trying the local \ncuisine, including " + adj1 + " " + fd1 + " and " + fd2 + ".")
print(" ")
print(name + " will have to practice the language " + adv + " to \nmake it easier to " + verb + " with people.")
print(" ")
print(name + " has a long list of sights to see, including the\n" + noun + " museum and the " + adj2 + " park.")
Explanation:
Got it right. Might be a longer version, but it worked for me.
Answer:
See explaination
Explanation:
Keep two iterators, i (for nuts array) and j (for bolts array).
while(i < n and j < n) {
if nuts[i] == bolts[j] {
We have a case where sizes match, output/return
}
else if nuts[i] < bolts[j] {
this means that size of nut is smaller than that of bolt and we should go to the next bigger nut, i.e., i+=1
}
else {
this means that size of bolt is smaller than that of nut and we should go to the next bigger bolt, i.e., j+=1
}
}
Since we go to each index in both the array only once, the algorithm take O(n) time.
