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3 years ago

Convert to an improper fraction. Type in your answer with the negative in the numerator. -11 1/3

Mathematics

2 answers:

vovangra [49]3 years ago

6 0

The answer to the question is :

-11*3+1/3
=-33+1/3
= -32/3

Therefore, answer = -32/3

prohojiy [21]3 years ago

5 0

-11 1/3 = -34/3 put the

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What is the value of y? A. 83 B. 89 C. 96 D. 97

Readme [11.4K]

Answer:

A. 83 is the correct option.

Step-by-step explanation:

all angles of a triangle are always equal to 180.

46 + 51 + y = 180

97 + y = 180

180 - 97 = 83

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3 years ago

This model of the backboard of a basketball goal is composed of a rectangle and a semicircle. What is the area of

irina1246 [14]

Answer:

deal with the rectangle first A = l X w

4 X 12 = 48 squared cm

semi circle

Area of a circle πr^2

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3 years ago

Review the attachments. Review the process of solving an equation and fill in the blanks.

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Answer:

1) Combine like terms

2) $\sqrt[3]{x} =3$

3) cube both sides of the equation

4) $4\sqrt[3]{27} +8\sqrt[3]{27}=36$

5) 4(3) + 8(3) = 36

Step-by-step explanation:

1) Combine like terms

2) $\sqrt[3]{x} =3$

3) cube both sides of the equation

4) $4\sqrt[3]{27} +8\sqrt[3]{27}=36$

5) 4(3) + 8(3) = 36

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2 years ago

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The correct answer is A. The base of the rectangular prism must be 12 units because the height is 2 units, and 2 multiplied by 12 is 24, which is the total volume of the prism.

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3 years ago

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So $\mu = 375, \sigma = 68$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So $n = 6, s = \frac{68}{\sqrt{6}} = 27.76$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 375}{27.76}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So $\mu = 522, \sigma = 106$