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Lady_Fox [76]
3 years ago
13

Problem that compares and 0.29

Mathematics
1 answer:
vaieri [72.5K]3 years ago
7 0
Harold Had Bought Two Ropes. The green rope was 0.29 m. and the blue one was 0.4 m. He Wanted To Give His Best Friend Harry The Longer One. Which Rope Should Harold give Harry?

(This Is An Example You Are Allowed To Use)
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A beach ball rolls off a cliff and onto the beach. The height, in feet, of the beach ball can be modeled by the function h(t)=64
Karolina [17]

Answer:

rate of change = -32 feet/second

Step-by-step explanation:

h(t) = 64 – 16t2

t = time (seconds)

Look at the start of time where t = 0

h(t) = 64 - 16 * (0) * 2 = 64 feet

Then look at the specified time where t = 1.25 seconds

h(t) = 64 - 16 * (1.25sec) * 2 = 24 feet

rate of change = rate of change y / rate of change x

x = time, y = height

rate of change = (24 - 64) / (1.25 - 0) = -32 feet/second

4 0
2 years ago
Read 2 more answers
A 4 metre ladder is placed against a vertical wall.
Black_prince [1.1K]

Answer:

Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.

Step-by-step explanation:

By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.

Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.

By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.

Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625

y^2-y^2+0.5y+2.25–4.0625=0

0.5y- 1.8125=0

0.5y=1.8125

y=1.8125/0.5= 3.625

Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder

Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625

L^2=13.140625–0.90625+4.0615=15.390625

L= (15.390625)^1/2= 3.92 meters length of ladder

<em>hope it helps...</em>

<em>correct me if I'm wrong...</em>

4 0
3 years ago
∠ABD is formed by a tangent and a secant intersecting outside of a circle. If minor arc AC = 72° and minor arc CD = 132°, what i
notsponge [240]
<span>you're given both arcs, minor and major, or near and far arcs, all you need to do, is really plug them in</span>

3 0
3 years ago
Can someone help me with this problem please
Makovka662 [10]

Answer:

Circumference=2πr or πd

So:

3.14 × 6cm

=18.84cm

6 0
2 years ago
You draw 1 card at random from a well-shuffled deck of 52 cards, put it back, reshuffle, and draw another card at random. The ev
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This answer would be true. I believe. It would be that because they are completely separate. 
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