I HAVE A FEW MINS PLEASE HEELPPP! FOR BRIANLIEST!

Mathematics

1 answer:

riadik2000 [5.3K]2 years ago

8 0

Answer:

For each of the possible outcomes add the numbers on the two dice and count how many times this sum is 7. If you do so you will find that the sum is 7 for 6 of the possible outcomes. Thus the sum is a 7 in 6 of the 36 outcomes and hence the probability of rolling a 7 is 6/36 = 1/6

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Mila [183]

<h3>Answer: 0.1319</h3>

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Work Shown:

$P(x) = (_n C_x)*(p)^x*(1-p)^{n-x}\\\\P(14) = (_{15} C_{14})*(0.8)^{14}*(1-0.8)^{15-14}\\\\P(14) = 15*(0.8)^{14}*(0.2)^{1}\\\\P(14) \approx 0.13194139533312 \\\\P(14) \approx \boldsymbol{0.1319} \\\\$

Side note: you can use the nCr formula to compute $_{15} C_{14}$ ; however, it's much quicker to use the shortcut formula $_{n} C_{n-1} = n$ . You can also use Pascal's Triangle to find the value of $_{15} C_{14}$