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3 years ago

HELP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE please

Mathematics

1 answer:

VMariaS [17]3 years ago

3 0

Answer:

50.5

Step-by-step explanation:

Sooo first we calculate edf. 11/2= 5.5, 5.5x5=27.5

And then we do the other part.9/5=4, and 4x11.5=46, and we need to cut that in half cuz it’s a triangle 46/2=23. We add up the rectangle and the triangle: 27.5+23=50.5

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7/8 x c for c =8. How do I figure out the answer to this problem?

kobusy [5.1K]

7/8 times 8
7/8 times 8/1
56 over 8
divide 56 by 8
the answer is 7.25 or 7 if you are rounding

3 0

3 years ago

With gasoline prices increasing, drivers are more concerned with their cars’ gasoline consump- tion. For the past 5 years, a dri

polet [3.4K]

Answer:

The calculated chi -square value =5.7356 Is less than12.01 at 0.1level of significance .

The null hypothesis is accepted.

The past 5 years, a driver has tracked the gas mileage of his car and found that the variance from fill-up to fill-up was σ2 = 23 mpg^2.

Step-by-step explanation:

Step:-(1)

Given data 28 25 29 25 32 36 27 24

Sample size 'n' = 8

mean of the sample (x⁻) = ∑x /n = $\frac{28+ 25+ 29 +25 +32 +36 + 27 + 24}{8}$

mean of the sample (x⁻) = 28.25

x x- x⁻ (x-x⁻ )²

28 28 - 28.25 = -0.25 0.0625

25 25 -28.25 = -3.25 10.56

29 29-28.25 = 0.75 0.5625

25 25-28.25 = -3.25 10.56

32 32-28.25 = 3.75 14.06

36 36-28.25 = 7.75 60.06

27 27-28.25 = -1.25 1.5625

24 24-28.25 = -4.25 18.06

∑(x-x⁻)² = 115.4875

Step:-(2)

The sample standard deviation

S² = ∑(x-x⁻)²/n-1 = $\frac{115.4875 }{7}$ = 16.49

By using χ² distribution

χ² = $\frac{ns^2 }{variance}$

By above test can be applied only if the population from which sample is drawn normal.

Given data For the past 5 years, a driver has tracked the gas mileage of his car and found that the variance from fill-up to fill-up was σ2 = 23 mpg^2.

Population variance σ² = 23

Step:-(3)

Null hypothesis :H₀:σ² = 23

Alternative hypothesis :H₁:≠23

$X^{2} = \frac{8 (16.49)}{23}=5.7356$

The calculated chi -square value =5.7356

The degrees of freedom γ=n-1 =8-1=7

The tabulated value of chi -square = 12.01 at 0.1level of significance (check table)

The calculated chi -square value =5.7356 Is less than12.01 at 0.1level of significance .

The null hypothesis is accepted.

Conclusion:-

The null hypothesis is accepted.

The past 5 years, a driver has tracked the gas mileage of his car and found that the variance from fill-up to fill-up was σ2 = 23 mpg^2.

5 0

3 years ago

10483 people attended a rock festival. if there were 811 more boys than girls, and 2481 fewer adults over 50 years of age than t

Bond [772]

Answer: 4051 girls, 4862 boys and 1570 adults over 50 years of age group attended the festival.

Step-by-step explanation:

Let x denotes the number of girls.

Then, the number of boys = x+811

The number of adults over 50 years of age = x-2481

Now, by considering the given scenario :-

$x+x+811+x-2481=10483\\\\\Rightarrow\ 3x-1670=10483\\\\\Rightarrow\ 3x=10483+1670\\\\\Rightarrow\ 3x=12153\\\\\Rightarrow\ x=\dfrac{12153}{3}=4051$