The probable genotype of the IV-3 with the perspective of autosomal inheritance will be A because he does not have condition A. Therefore both parents must be in condition A.
The probable genotype of IV-3 with the perspective of set=linked inheritance will be BbY this is because he has B condition. Therefore the mothers' genotype must be XBXb and the father's genotype must be XBY.
The probability of IV-4 having condition A is 1/36
Answer:
in plants is responsible for the timing of seasonal activities such as flowering and growth.Transpiration is the loss of OXYGEN through a plant's leaves. False- water. When the guard cells of a leaf lose water, the stomata OPEN.
Explanation:
so the answer is True
Answer:
maybe
Explanation: both idk for sure sry i tried
Answer:
Ok, how is this a question?
The statement is true though!
