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nasty-shy [4]
3 years ago
9

I need help with this equation 20 points help quick

Mathematics
1 answer:
Flura [38]3 years ago
7 0

Answer:

\boxed{y=|\frac{1}{2}x  - \frac{3}{2}|+3}

Step-by-step explanation:

The translation is a horizontal translation.

The graph is translated 1 unit to the left. So the value of x is added by 1.

f(x+1)

y=|\frac{1}{2} (x+1)-2|+3

y=|\frac{1}{2}x + \frac{1}{2} -2|+3

y=|\frac{1}{2}x + - \frac{3}{2}|+3

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Our pool is twice as long as it is wide and is surrounded by a walkway of uniform width of 1 foot. The
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Step-by-step explanation:

x=width of pool

2x=length of pool

the dimensions of the rectangle forming the walkway and the pool are x+4 and 2x+4

the area of this rectangle minus the area of the pool is 196 square feet

(2x+4)(x+4)-(x)(2x)=196

2x^2+4x+8x+16-2x^2=196

combine similar terms

12x+16=196

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12x=180

x=180/12

x=15 feet is the width of the pool

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646-450=196

196=196

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