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olga2289 [7]
3 years ago
5

20 ft = how many yards and how many feet?

Mathematics
2 answers:
tiny-mole [99]3 years ago
5 0
6.67 yardssssssssssssssss
Anestetic [448]3 years ago
3 0

Answer:

6 yards 2 feet

Step-by-step explanation:

3ft in a yard 20/3 = 6.666 or 6 yards 2 feet

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Answer:

35000

Step-by-step explanation:

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3 years ago
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A ping pong ball has a 75% rebound ratio. When you drop it from a height of k feet, it bounces and bounces endlessly. If the hei
ratelena [41]

The movement of the ping pong ball follows a exponential progression.

  • The expression for the k-th bounce is: \mathbf{T_k = 235 \times (0.75)^k}
  • The height after the 6th bounce is 41.82 ft
  • The total distance after the 12th bounce is 1584.84ft.
  • There will be 31457280 bacteria after a day and a half.

<u />

<u>1. Ping pong ball</u>

The given parameters are:

\mathbf{a = 235} --- the initial height

\mathbf{r = 75\%} --- the common ratio

<u>(a) The expression after bouncing k times</u>

To do this, we make use of

\mathbf{T_n = a \times r^n}

So, we have:

\mathbf{T_n = 235 \times (0.75)^n}

In this case; k = n.

So, the equation becomes

\mathbf{T_k = 235 \times (0.75)^k}

Hence, the expression for the k-th bounce is: \mathbf{T_k = 235 \times (0.75)^k}

<u />

<u>(b) The height after bouncing 6 times</u>

This means that k = 6.

So, we have:

\mathbf{T_k = 235 \times (0.75)^k}

\mathbf{T_6 = 235 \times (0.75)^6}

\mathbf{T_6 = 41.82}

Hence, the height after the 6th bounce is 41.82 ft

<u>(c) The total distance after the 12th bounce</u>

First, we calculate the total height after the 12th bounce using:

\mathbf{S_k = \frac{a(1 - r^k)}{1 - r}}

So, we have:

\mathbf{S_k = \frac{235 \times (1 - 0.75^{12})}{1 - 0.75}}

\mathbf{S_k = \frac{235 \times (0.968)}{0.25}}

\mathbf{S_k = 909.92}

So, the total distance is:

\mathbf{Distance = 2 \times S_k - a}

\mathbf{Distance = 2 \times 909.92 - 235}

\mathbf{Distance = 1584.84}

Hence, the total distance after the 12th bounce is 1584.84ft.

<u>(2) Cell division</u>

The given parameters are:

<em />\mathbf{r = 2/2hr}<em> --- rate</em>

<em />\mathbf{a = 120}<em> --- initial number of cells</em>

<em />\mathbf{t = 18}<em> --- number of 2 hours is a day and a half</em>

<em />

So, the number of bacteria is:

\mathbf{T_t = ar^t}

This gives

\mathbf{T_t = 120 \times 2^{18}}

\mathbf{T_t = 31457280}

Hence, there will be 31457280 bacteria after a day and a half.

Read more about exponential functions at:

brainly.com/question/11487261

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3 years ago
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Answer:

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What is the product of k and 8
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Answer:

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if you multiply a number and a variable then they combine to make the equation the answer rather than a single number so your answer would be 8k

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Write the word form for 300,000,000,000
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