We have that
<span>Circle 1: center (8, 5) and radius 6
</span><span>Circle 2: center (−2, 1) and radius 2
we know that
the equation of a circle is
(x-h)</span>²+(y-k)²=r²
for the circle 1---------> (x-8)²+(y-5)²=36
for the circle 2---------> (x+2)²+(y-1)²=4
using a graph tool
see the attached figure
Part A)<span>What transformations can be applied to Circle 1 to prove that the circles are similar?
we know that
r1/r2---------> 6/2------> 3
</span><span>
to prove that the circle 1 and circle 2 are similar, the radius of circle 1 </span>must be divided by 3 and translate the center of the circle 1 (10) units to the left and (4) units down
<span>
the answer part A) is
</span>
the radius of circle 1 must be divided by 3 and translate the center of the circle 1 (10) units to the left and (4) units down
Part B) <span>What scale factor does the dilation from Circle 1 to Circle 2 have?
the answer Part B) is
the scale factor is (3/1)</span>
A shape that is similar to another shape will be enlarged by a scale factor.
Each corresponding sides should give the same scale factor
Side GI corresponds to side JL
Side GH corresponds to side JK
Side HI corresponds to side KL
The correspond sides whose length are given is
GH = 4 and JK = 8
Side JK is twice longer than GH
All the other sides of triangle JKL are twice longer than triangle GHI, so we want that the side JL to be twice of the sides GI
Side GI = 6
Side JL = 6 × 2 = 12
Answer: y = 12
Answer:
C. 2.5×10^-27
Step-by-step explanation:
(2×10^-13)^-2 = 2^-2 × 10^(13×(-2)) = 1/4 × 10^-26
= 0.25 × 10^-26 = 2.5 × 10^-27
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Your scientific or graphing calculator can compute and display this for you.
It would be two places to the right of 0 because -3+5=2