1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:
a^{2}=b ^{2}+c ^{2}-2bc(cosA)
2.
20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA) 400=81+169-234(cosA) 150=-234(cosA) cosA=150/-234= -0.641
3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
Answer:
4.9%
Step-by-step explanation:
6600 * 107/100 = 66*107 = 7062.
3500 * 101/100 = 35x101 = 3535
7062+3535=10597. Original worth: 10100
10597-10100 = 497
497/10100 = 0.0492079208, or 4.92%, rounds to 4.9%
Answer:
Hyperbola.
Step-by-step explanation:
We start from the function:
We may get the traces if we cut the surface in planes x=k. This is equivalent to replace x for k:
The last equation is the equation of an hyperbola, which varies its characteristics depending on K (the plane cut).
Answer:5 exponent of 15
Step-by-step explanation:trust
Yes you are correct. You divide both sides by -6 to isolate x. Dividing both sides by a negative number will flip the inequality sign.
If you need to graph this, then you'll have a closed circle at -12 on the number line. Then you'll have shading to the left of this closed circle. The closed circle indicates "include this endpoint as part of the shaded solution set".
