Answer:
x = -4, x = 1
Step-by-step explanation:
Now I do not know why you said done, but just saying, if you are done with a question, you should delete it. Now I am just going to assume you knew this and move on with the solution of the problem.
When you factor this equation, you will get (x+4)(x-1).
You can then solve for x using zero product property. The first root is -4 and the second root is 1.
Answer:
yes
Step-by-step explanation:
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TU=13; UV= 13; TV=26
Step-by-step explanation:
Hope this helped!
Plug x = 0 into the function
f(x) = x^3 + 2x - 1
f(0) = 0^3 + 2(0) - 1
f(0) = -1
Note how the result is negative. The actual number itself doesn't matter. All we care about is the sign of the result.
Repeat for x = 1
f(x) = x^3 + 2x - 1
f(1) = 1^3 + 2(1) - 1
f(1) = 2
This result is positive.
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We found that f(0) = -1 and f(1) = 2. The first output -1 is negative while the second output 2 is positive. Going from negative to positive means that, at some point, we will hit y = 0. We might have multiple instances of this happening, or just one. We don't know for sure. The only thing we do know is that there is at least one root in this interval.
To actually find this root, you'll need to use a graphing calculator because the root is some complicated decimal value. Using a graphing calculator, you should find the root to be approximately 0.4533976515
The second option: 4x² - x + 1
All you have to do is add the like terms:
3x² + x² = 4x²
4x - 5x = -x
-2 + 3 = 1
Combine all the results and you will get your solution!