Answer:

Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
we know that
The measure of the external angle is the semi-difference of the arches it covers.
so
![m\angle GET=\frac{1}{2}[arc\ TN-arc\ TG]](https://tex.z-dn.net/?f=m%5Cangle%20GET%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20TN-arc%5C%20TG%5D)
Remember that the diameter divide the circle into two equal parts
In this problem
TN is a diameter
we have
----> because is half the circle (TN is a diameter)
---> is given
substitute
![m\angle GET=\frac{1}{2}[180^o-46^o]=67^o](https://tex.z-dn.net/?f=m%5Cangle%20GET%3D%5Cfrac%7B1%7D%7B2%7D%5B180%5Eo-46%5Eo%5D%3D67%5Eo)
Answer:
I'll probably come back and do this later.
Step-by-step explanation:
<u>How to Round:</u>
If the number following the number you're going to round up is 5 or above, (5, 6, 7, 8, or 9), then round up. (E.X. 2<u>9</u> rounded up is 30. Since 9 is above 5, you will round up.
On the other hand, if the number following the number you're going to round is 4 or below, (4, 3, 2, or 1), you don't round up, instead you keep it the same, and if they're are decimals, you turn the following numbers to 0s. (E.X. 32.4536 rounded to the nearest hundredth (32.45<u>3</u>6) is 32.45. Since 3 is less than 4, you're not going to round up. The number in the hundredth's place stays the same (5), and the following rest turn to 0s. Leaving you with 32.45
Let me know if this helped. :)
Answer:
M and P
Step-by-step explanation:
they do not cross each other
The answer is
a) 11/15
b) 1/18