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faltersainse [42]
3 years ago
12

Find the perimeter of a triangle with vertices A(–3, 5), B(–3, 2), and C(1, 2) Show all work

Mathematics
1 answer:
Luden [163]3 years ago
7 0

Answer:

perimeter= 12units

Step-by-step explanation:

steps are in picture

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Pls help me! i’m really confuse on how to tackle this problem (no links)
bonufazy [111]

Answer:

Step-by-step explanation:

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3 years ago
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Solve with the law of sine
Zinaida [17]

1) Triangle QRT, where q = 32.4 ft, r = 29.8 ft, t = 42.1 ft

No this cannot make a second triangle

2) Triangle ABC, where B = 62°, a = 11.52 m, c = 19.34 m

No this cannot make a second triangle

3) Both of the triangles cannot make a second triangle

<h3>How does law of sine work</h3>

The following is a detailed explanation of the sine law: In a triangle, side "a" divided by angle sine "a" equals side "b" divided by angle sine "b" equals side "c" divided by angle sine "c."

The formula for law of sine is written as

Sine A  a = Sine B/ b = Sine C / c

These law helps in determining the given angles and sides

For the situation given; both cannot be used to make a second triangle

Learn more about conditions Infinite number of triangles at:

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5 0
2 years ago
At the skateboard park, the hot new attraction is the U-Dip, a cement structure embedded into the ground. The cross-sectional vi
Ratling [72]

Answer:

hahsbsaagvsaagags

Step-by-step explanation:

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7 0
3 years ago
Verify that the roots of 5x²- 6x -2 = 0 are <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%20%2B%20%5Csqrt%7B19%7D%20%7D%7B5%7D%2
Mice21 [21]

Answer:

Proof below.

Step-by-step explanation:

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

<u>Given quadratic equation</u>:

5x^2-6x-2=0

<u>Define the variables</u>:

  • a = 5
  • b = -6
  • c = -2

<u>Substitute</u> the defined variables into the quadratic formula and <u>solve for x</u>:

\implies x=\dfrac{-(-6) \pm \sqrt{(-6)^2-4(5)(-2)}}{2(5)}

\implies x=\dfrac{6 \pm \sqrt{36+40}}{10}

\implies x=\dfrac{6 \pm \sqrt{76}}{10}

\implies x=\dfrac{6 \pm \sqrt{4 \cdot 19}}{10}

\implies x=\dfrac{6 \pm \sqrt{4}\sqrt{19}}{10}

\implies x=\dfrac{6 \pm2\sqrt{19}}{10}

\implies x=\dfrac{3 \pm \sqrt{19}}{5}

Therefore, the exact solutions to the given <u>quadratic equation</u> are:

x=\dfrac{3 + \sqrt{19}}{5} \:\textsf{ and }\:x=\dfrac{3 - \sqrt{19}}{5}

Learn more about the quadratic formula here:

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2 years ago
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If the cost price of a bag is AED 2176 and its selling price is AED 2497 then find the profit
ICE Princess25 [194]

Answer:

321 AED

Step-by-step explanation:

2497 - 2176 = 321 AED

6 0
3 years ago
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